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galina1969 [7]
2 years ago
9

Hart Technology must accrue a loss contingency. The amount of the loss can be reasonably estimated within a range of outcomes. O

f these outcomes, no single amount within the range is a better estimate than any other amount, but the attorneys have determined that the most probable amount to be paid by Hart Technology would be the minimum amount. What amount of loss accrual should Hart recognize
Business
1 answer:
Shtirlitz [24]2 years ago
3 0

The amount of loss that should be recognized is the <u>minimum amount </u><u>of the </u><u>range. </u>

<u />

<h3>Recording a Contingent liability </h3>
  • It should only be recorded if the loss is probable and the amount to be incurred as liability can be reasonably estimated.
  • If neither of the above are possible, the loss would be recorded as a footnote.

US GAAP rules state however that if the loss is probable and the amount is in a range, the amount to be recorded as a contingent liability should be the minimum of the range.

In conclusion, they should recognize the minimum amount.

Find out more on contingent liabilities at brainly.com/question/17371330.

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Select the items below that are examples of things that could use the smart card
kogti [31]
What are the items?
3 0
3 years ago
Dr. Jones’ office has purchased the above equipment. It is now Year #2 and there is a $7,000 annual maintenance fee that needs t
Paul [167]

The Loss recorded in the year 2 for the table is -$35,841.39.

<h3>What is the profit or loss on the table? </h3>

<u>Year 2 </u>

Monthly Cost in year  $1564.29

Maintenance               $0  

Salary                          $39600

Fixed cost                   $0

Variable cost              <u>$356.40</u>

Total cost                   <u>$41520.69</u>

Reimbursements = $5679.30

Profit or Loss = Reimbursements - Total cost

Profit or Loss = $5679.30 - $41520.69

Loss =  -$35,841.39.

Read more about Profit or Loss

<em>brainly.com/question/17515276</em>

#SPJ1

3 0
1 year ago
Hawke Company had the following assets and liabilities on the dates indicated. December 31 Total Assets Total Liabilities 2019 $
sdas [7]

Answer:

2019:- 62000 Income ; 2020:- 24000 loss ;  2021:- 43000 Income

Explanation:

Assets - Liabilities = Capital   (Closing / Opening both)

Profit = Closing Capital - Opening Capital + Drawings - Additional Capital

(Opening Capital = 1st Jan , Closing Capital = 31st Dec) here

2019

Closing Capital = Closing Assets - Closing Liabilities  

400000 - 250000 = 150000

Profit = Closing Capital - Opening Capital + Drawings - Additional Capital

= 150000 - 100000 + 12000 =  62000 Income

2020

2020 Opening Capital = 2019 Closing Capital = 150000

Closing Capital =  Closing Assets - Closing Liabilities  

460000 - 300000 = 160000

Profit = Closing Capital - Opening Capital + Drawings - Additional Capital

160000 - 150000 - 34000 = 24000 loss

2021

2021 Opening Capital = 2020 Closing Capital = 160000

Closing Capital =  Closing Assets - Closing Liabilities  

590000 - 400000 = 190000

Profit = Closing Capital - Opening Capital + Drawings - Additional Capital

190000 - 160000 + 25000 - 12000 = 43000 Income

4 0
3 years ago
For various reasons related to trying to prevent a catastrophic recession during the pandemic, the federal government has and wi
Novosadov [1.4K]

Answer:

$0.316 trillion per annum

Explanation

According to the scenario, computation of the given data are as follow:-

Interest rate = 0.5% = 0.005

Government Borrows = $6 trillion

Time = 20 years

Required Uniform Annual Payment= Government Borrows × Interest Rate × [(1 + Interest Rate)^Time period ÷ (1 + Interest Rate)Time period] - 1

= $6 trillion × 0.005 × [(1 + 0.005)^20 ÷ (1 + 0.005)^20 - 1]

= $0.03 trillion × [(1.005)^20 ÷ (1.005)^20 - 1]

= $0.03 trillion × (1.1049 ÷ 1.1049 - 1)

= $0.03 trillion × (1.1049 ÷ 0.1049)

= $0.03 trillion × 10.533

= $0.316 trillion per annum

3 0
3 years ago
You have just applied for a 30year 100000 mortgage at a rate of 10%.what must be annual payment be?​
Fittoniya [83]

Answer:

The correct answer is "$10,607.92".

Explanation:

Given:

Amount borrowed,

P = 100000

Interest rate,

r = 10%

or,

 = 0.1

Time,

= 30 years

Now,

The annual payment will be:

⇒ A=P\times \frac{r(1+r)^n}{(1+r)^n-1}

       =100000\times \frac{0.1(1+0.1)^{30}}{(1+0.1)^{30}-1}

       =10,607.92 ($)

7 0
2 years ago
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