All categories

1 year ago

Please hurry

Mathematics

2 answers:

Luda [366]1 year ago

6 0

Answer:

Yes.

10y = x

or x / 10 = y

or x / y = 10

Step-by-step explanation:

20 / 2 = 10

50 / 5 = 10

60 / 6 = 10

70 / 7 = 10

ella [17]1 year ago

5 0

Answer:

Yes x and y do have a proportional relationship because with every 10 copies of paper the value of y goes up by 1 meaning that it would have a constant rate of change equal to 1/10

You might be interested in

Katherine went to Hibbet sports and spent $125.50 on a pair of shoes and $12.25

Sergio039 [100]

Answer:

1. $137.75

3. $149.15

Step-by-step explanation:

12.25+125.50=137.75

3. 8.25% of 137.75= 11.4

137.75+11.4=149.15

3 0

2 years ago

Read 2 more answers

4 /5 fraction can be rewritten as _____

patriot [66]

Answer:

8/10, 12/15, 16/20 and so on

Step-by-step explanation:

4x2/5x2 = 8/10
4x3/5x3 = 12/15
4x4/5x4 = 16/20 and so on

3 0

1 year ago

Jenny purchased a prepaid phone card for $30.Long distance calls cost 12 cents a minute using this card. Jenny used her card onl

Korolek [52]

Answer:

43 min

Step-by-step explanation:

subtract $24.84 from $30 and you get $5.16 and you divide that by 12 cents which then you get 43 min

4 0

2 years ago

A picture of a cougar is 3/4in long, and the legend below it says 1 : 80. How long is the actual cougar?

stealth61 [152]

Basically the real one is 80 times the picture
80 times 3/4=80/1 times 3/4=240/4=60in=5ft
it is 5ft long or 60in

8 0

3 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago