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2 years ago

Solve for x then find the measure of the angle given

Mathematics

1 answer:

ololo11 [35]2 years ago

8 0

Answer:

∠ MPQ = 125°

Step-by-step explanation:

∠ LMN and ∠ MPQ are corresponding angles and are congruent , so

5x = 3x + 50 ( subtract 3x from both sides )

2x = 50 ( divide both sides by 2 )

x = 25

Then

∠ MPQ = 3x + 50 = 3(25) + 50 = 75 + 50 = 125°

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Solve the inequality 12(1/2x-1/3)>8-2x

gizmo_the_mogwai [7]

Answer:8(1/2x - 1/4)> 12 - 2x

a.x > 7

b.x > 7/3

c.x > 5/3

d.x > 5/3

Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x

3 0

3 years ago

Why are the solutions to the proportions 40/8 = x/10 and x/40 = 10/8 the same?

romanna [79]

Answer:

Both proportions are equivalent.

Step-by-step explanation:

We have been given two proportions $\frac{40}{8}=\frac{x}{10}$ and $\frac{x}{40}=\frac{10}{8}$ . We are asked to find why the solutions to our given proportions are equal.

We can solve proportions by cross multiplying them.

After cross multiplying our both proportions we will get same equation that is:

$40*10=8*x$

$400=8x$

$8*x=40*10$

$8x=400$

Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.

4 0

3 years ago

Read 2 more answers

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

3 years ago

Given the following sequence, find the 14th term: 3, 1, –1, –3, –5, . . .

AVprozaik [17]

3, 1, -1, -3, -5
-2 -2 -2 -2

a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
a₁₄ = -2(14) + 5
a₁₄ = -28 + 5
a₁₄ = -23

The answer is C.

7 0

3 years ago

Read 2 more answers

Need help on 8th grade algebra I’ll give Brainly to whoever answers

RideAnS [48]

Answer:

its the second one

Step-by-step explanation:

hope it helps

7 0

3 years ago