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Ivanshal [37]
2 years ago
14

How do u make this 4/4?

Mathematics
1 answer:
Oksana_A [137]2 years ago
8 0

well, if look at the timetable, She got the 08:30am train from Aberystwyth and arrives on time at Shrewsbury, from the timetable we know she arrived at 10:17am, now she did some rigamarole and got back to the Train station at Shrewsbury 4 hours later.  Well, we know she arrived at 10:17am, if we add 4 hours to that that'll make it 1417 or namely 2:17pm.

well, the Train arrives at Shrewsbury a 14 19, or 2:19pm, she is there at 2:17pm, so she's really 2 minutes before the Train arrives at Shrewsbury, she's right on time, possibly with some munchies too.

14 19 > 14 17.

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ZanzabumX [31]

Answer:

Step-by-step explanation:

\left[\begin{array}{ccc}7&31\\142&19\end{array}\right] = 7(19) - 142(31) = <em>- 4269</em>

\left[\begin{array}{ccc}7&11&21\\55&-8&2\\-16&-1&-9\end{array}\right] = 7(- 8)(- 9) + 11(2)(- 16) + 21(55)(- 1) - 21(- 8)(- 16) - 7(2)(- 1) - 11(55)(- 9) = <em>1768</em>

\left[\begin{array}{ccc}9.07&6.02&2.01\\-30.7&2.5&3.5\\3.55&-1.1&2.35\end{array}\right] = 9.07(2.5)(2.35) + 6.02(3.5)(3.55) + 2.01(- 30.7)(- 1.1) - 2.01(2.5)(3.55) - 9.07(3.5)(- 1.1) - 6.02(- 30.7)(2.35) = <em>647.3561</em>

4 0
3 years ago
Find the solution to the system of equations.
Vikentia [17]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
When the turnpike littered the toll, traffic increased from 1,500 cars per day to 2,700
umka21 [38]

Answer:

  80%

Step-by-step explanation:

The percentage change between two numbers can be calculated as ...

  percentage change = ((new value)/(old value) -1) × 100%

  = (2700/1500 -1) × 100% = (1.80 -1) × 100% = 80%

Traffic volume increased 80%.

6 0
3 years ago
In order to solve the system of linear equations, the coefficients of one of the variables must be the same number but opposite
Mashutka [201]

Answer:

Step-by-step explanation:

because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number  so that there will be at least one variable with the same number but with opposite signs.

it does not matter which variable you choose.

lets use y because 2 and 3 are smaller then 2 and 5.

so lets multiply the first equation by 2 in order to get y equal to 6.

2(2x)+2(3y)=(2)6

(do not forget to multiply what the equation is equal to also)

4x+6y=12

now for the second equation we need y to equal negative 6

-3(5x)+-3(2y)=-3(4)

-15x-6y=-12

now lets put the 2 new equations next to each other and see what we can cancel out

4x+6y=12

-15x-6y=-12

-11x=0

x=0

now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.

2(0)+3y=6

3y=6

y=2

so your answer is x=0, y=2

8 0
3 years ago
Help. please <br><br><br> &amp;-&amp;-&amp;-&amp;/&amp;/&amp;/$72
DIA [1.3K]

Answer:

Step-by-step explanation:

Enter your x and y values into your equation from your table

7 0
3 years ago
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