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2 years ago

What is the value of 36x-8y^2 when x=3 and y= -6?

Mathematics

1 answer:

Zepler [3.9K]2 years ago

7 0

Answer:

-6 gets canceled out because it gets squared. When you square a number, you multiply it by itself. Any negative number times a negative number results in a positive number. So instead of -36 its just 36

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What number is 20% of 80? HELPPP!

blondinia [14]

Answer:

Please list as brainlist so that I can level up! Thank You!

Hope this helps!!!!!!!!

Step-by-step explanation:

Remember 20% = 0.20 or 0.2

so 20% x 80 = 0.2 x 80 = 16

7 0

3 years ago

Read 2 more answers

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

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2 years ago

The sum of two consecutive integers is 77. Find the integers.

SIZIF [17.4K]

Answer:

38 and 39

Step-by-step explanation:

Since the two integers are consecutive, then one is one larger than the other. Therefore, lets call them x and x+1. We can now set up the following equation:

x+(x+1)=77

2x+1=77

2x=76

x=38

x+1=39

Hope this helps!

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3 years ago

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OverLord2011 [107]

Answer