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ch4aika [34]
3 years ago
11

An animal shelter spends $2.50 per day to care for each bird and $7.50 per day to care for each cat. Allison noticed that the sh

elter spent $62.50 caring for birds and cats on Monday. Allison found a record showing that there were a total of 19 birds and cats on Monday. How many birds were at the shelter on Monday?
Mathematics
1 answer:
kykrilka [37]3 years ago
6 0
Answer = 16 birds

1. Write out your equations
X = birds
Y= cats
x + y = 19
2.50x + 7.50y = 62.50

2. Isolate one variable.
x + y = 19
x = 19 - y

3. Plug this in as the variable in the other equation. Then, solve.
2.5(19 - y) + 7.5y = 62.5
47.5 - 2.5y + 7.5y = 62.5
-2.5y + 7.5y = 15
5y = 15
y = 3 (cats)

4. Solve for the other variable.
We know there were 19 animals in total on Monday. Since there were 3 cats, there must be 16 birds.

5. Double check by plugging the numbers into the original equations.
16 + 3 = 19
19 = 19 (true)

2.5(16) + 7.5(3) = 62.5
40 + 22.5 = 62.5
62.5 = 62.5 (true)
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In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
PLEASE HELPPPP!!!!!!
Sloan [31]

Step-by-step explanation:

y=kx

say that y is the original prince and x is the sale price

15=k(10)

15/10=k

3/2=k

you can check with the next problem to check if it is the same

25=k(20)

25/20=k

5/4=k

so you take 5/4-3/2=-1/4 so the constant is -1/4

Hope that helps :)

8 0
2 years ago
In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalizat
Viktor [21]

Answer:

Sample mean for solution 1:  19.27; sample mean for solution 2:  10.32

Step-by-step explanation:

To find the sample mean, find the sum of the data values and divide by the sample size.

For solution 1, the sum is given by:

9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7

The sample size is 10; this gives us

192.7/10 = 19.27

For solution 2, the sum is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10, this gives us

103.2/10 = 10.32

6 0
3 years ago
Jocelyn is making flower arrangements for a party and has a choice of 9 carnations, 12 daffodils, and 12 tulips. Jocelyn would l
photoshop1234 [79]

The total arrangements Jocelyn can make is 239573160 if Jocelyn is making flower arrangements for a party and has a choice of 9 carnations, 12 daffodils, and 12 tulips.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

Jocelyn is making flower arrangements for a party and has a choice of 9 carnations, 12 daffodils, and 12 tulips.

Arrangements for carnations = P(9, 6) = 60480

Arrangements for daffodils = P(12, 4) = 11880

Arrangements for tulips = P(12, 4) = 239500800

Total arrangements = 60480 + 11880 + 239500800 = 239573160

Thus, the total arrangements Jocelyn can make is 239573160 if Jocelyn is making flower arrangements for a party and has a choice of 9 carnations, 12 daffodils, and 12 tulips.

Learn more about permutation and combination here:

brainly.com/question/2295036

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4 0
10 months ago
Please answer and say what a perfect root is pls i didnt get time to study and this is for 15 points
mixer [17]

Answer:

81

Step-by-step explanation:

9 x 9 = 81

So, 81 is the perfect square.

5 0
2 years ago
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