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Brilliant_brown [7]
3 years ago
9

What is the purpose of interphase, mitosis, and cytokinesis?

Biology
2 answers:
lana66690 [7]3 years ago
7 0
Mitosis is cell division that controls growth repair and replacement of cells. The steps of mitosis are prophase, metaphase, anaphase and telophase
Rainbow [258]3 years ago
3 0
These are all phases of cells multiplying without this we would all be one cell organisms
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TRUE OR FALSE<br> Oxygen is absorbed into the bloodstream in the trachea?
Arte-miy333 [17]

False. Oxygen is absorbed in the alveoli sacs of the lungs.

Upon inhalation Air must first pass through the larynx and down to the trachea, which then splits off into two separate bronchial tubes, the bronchial tubes divide into smaller air passages known as the bronchi and those into even smaller bronchioles. The bronchioles end in tiny sacs called the alveoli which transfer the oxygen from the inhaled air to the bloodstream.

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3 years ago
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Most of the light from the Sun is in which part of the electromagnetic spectrum? A. X-ray B. radio C. visible D. microwave
pochemuha
The best one is probably  D
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Which statement is one component of the cell theory?
Wittaler [7]

The options attached to the question above are given below:

A. All living and nonliving things consist of one or more cells.

B. Cells and living organisms are spontaneously created.

C. Cells are the most complex unit of structure and function in living things.

D. A cell is the basic unit of structure and function of all organisms

ANSWER

The correct option is D.

The cell theory is one of the major theories in biology and it states the facts about living cells. The theory states that, the cell is the most basic unit of all organisms and all living organisms are made up of one or more cells. The organisms that are made up of only one cell are described as unicellular while those that possess many cells are described as multi cellular. The theory also states that all cells come from pre-existing cells.



7 0
3 years ago
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What is an organisms niche
fredd [130]
In ecology<span>, a </span>niche<span> (</span>CanE<span>, </span><span><span>UK:</span> <span>/<span>ˈniːʃ</span>/</span></span><span> or </span><span><span>US:</span> <span>/<span>ˈnɪtʃ</span>/</span></span>)[1] is the fit of a species living under specific environmental conditions.
<span>https://en.wikipedia.org/wiki/Ecological_niche</span>
3 0
3 years ago
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Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
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