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julia-pushkina [17]
2 years ago
9

5 + 1 7/8 and explain answer

Mathematics
1 answer:
anzhelika [568]2 years ago
8 0

Answer:

6 7/8

Step-by-step explanation:

To evaluate 5 + 1 7/8 we combine the integers 5 and 1 and to this sum add the fraction 7/8:

5 + 1 + 7/8 = 6 7/8 (six and seven eighths)

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Printing machine A and printing machine B print the same newspaper printout, but machine B prints at half the rate of machine A.
klemol [59]

Answer:

The answer is below

Step-by-step explanation:

Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:

y = (1/2)x                       (1)

Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:

200/x + 200/y = 4       (2)

Put y = (1/2)x in equation:

\frac{200}{x}+\frac{200}{(\frac{1}{2} )x}=4\\ \\ \frac{200}{x}+\frac{400}{x}=4\\\\Multiply\ through\ by\ x:\\\\200+400=4x\\\\4x=600\\\\x=150

Put x = 150 in equation y:

y=(1/2)150 = 75

Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour

6 0
3 years ago
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
Combine like terms in (3x+5)+(4x-30
tresset_1 [31]

Answer:

The answer is 7x-25

Step-by-step explanation:

(3x+5)+(4x-30)

=3x+4x+5-30

=7x-25

3 0
3 years ago
Read 2 more answers
A​ 12-sided die is rolled. The set of equally likely outcomes is​ {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling
solniwko [45]
Need help with this , u think u can help?

6 0
2 years ago
Read 2 more answers
Solve each equation for the unknown <br>1. 5 + y = 7.<br>2. 3.8 = a + 2.5<br>5. + p = 9 1/3 ​
Alexxandr [17]

Answer:

1. 5 + y = 7

⇒ y = 7 - 5

⇒<u>y = 5</u>

2.  3.8 = a + 2.5

⇒ a = 2.5 - 3.8

⇒ <u>a = -1.3</u>

3. 5 + p = 9 1/3 ​

⇒ p = 9 1/3 - 5

⇒ p = 28/3 - 5

⇒ p = 28/3 - 15/3

⇒ p = 13/3

⇒<u> </u><u>p = 4 1/3</u>

3 0
3 years ago
Read 2 more answers
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