So... our numbers... let's say the first one is hmmm "a"
so the second and subsequent are
a
a+1
a+2
a+3
a+4
there, 5 consecutive whole numbers or integers for that matter
now, we know the sum of the square of the first three,
is the same as the sum of the square of the last two
so
![\bf \begin{cases} a\\ a+1\\ a+2\\ \textendash\textendash\textendash\textendash\\ a+3\\ a+4 \end{cases}\qquad (a)^2+(a+1)^2+(a+2)^2=(a+3)^2+(a+4)^2](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Aa%5C%5C%0Aa%2B1%5C%5C%0Aa%2B2%5C%5C%0A%5Ctextendash%5Ctextendash%5Ctextendash%5Ctextendash%5C%5C%0Aa%2B3%5C%5C%0Aa%2B4%0A%5Cend%7Bcases%7D%5Cqquad%20%28a%29%5E2%2B%28a%2B1%29%5E2%2B%28a%2B2%29%5E2%3D%28a%2B3%29%5E2%2B%28a%2B4%29%5E2)
do a binomial theorem expansion on those, solve for "a"
Answer:#of dimes is 15 # of quarters is 10
Step-by-step explanation:method is elimination my multiplication. First equation is x+y=25 multiply it by -10. Second equation is 10x+25y=400. A quarter is .25 and a dime is .10 but to avoid all decimals I multiplied by 10 but it doesn’t matter because I did it on both sides. Use systematic equation solving to get 15y=150 then y=10. Plug it into the first to get x+10=25 subtract to get 15. Mr. Jacobs does get excessive sometimes lol.
Answer: the 1 then the two bottom one
Step-by-step explanation:
herei s your answer plz let me know if you gotit right but plz rate me the most brainlest
Answer:
Given:
The distances, in yards, that a team moves on its first five plays are 2, 21, 4, 3, and 25.
Solved:
1. The greatest number is 25
2. If the moved distances are square, which one is largest?
3. The move which is greater than 4 is considered "big play"
=> 21 and 25 are big play (21 > 4, 25 > 4)
Hope this helps!
:)