The zeros of the function are 0 and 2
The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

<h3>Zeros and multiplicities of functions</h3>

Given the function $y=x(x-2)^3$

The zeros of the function is at the point where y = 0

$x(x-2)^3 =0\\x = 0\\(x-2)^3=0\\x-2=0\\x=2$

Hence the zeros of the function are 0 and 2

The multiplicity is the power to which the factors are raised. The multiplicities of the function are 1 and 3.

Learn more on zeros and multiplicity here: brainly.com/question/11314797

6 0

2 years ago

Select the margin of error that corresponds to the sample mean that corresponds to each population:

shusha [124]

Answer:

(351.04, 368.96)

4 0

3 years ago

Read 2 more answers

The top of two poles of height's 20m and 14m are connected by the wire

Hatshy [7]

Answer:

The correct option is;

10 m

Step-by-step explanation:

The parameters given are;

Height of the first pole = 20 m

Height of the second pole = 14 m

The angle the wire connected to their top makes with the horizontal = 30°

The vertical height subtended by the inclined wire, h = The difference in height between the two poles = 20 - 14 = 6 m.

Let the horizontal distance between the two poles = D

Therefore;

The horizontal length of the wire = D

From trigonometric ratios, we have;

$tan(30 ^{\circ}) = \dfrac{h}{D} = \dfrac{6}{D}$

Which gives;

$D = \dfrac{6}{tan(30 ^{\circ}) } = 10.39 \ m\approx 10 \ m$

The correct option is 10 m.

5 0

3 years ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

3 years ago