Answer:
0.15%
Step-by-step explanation:
We have been given that IQ scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 12. We are asked to find the percentage of IQ scores that are greater than 133 using the empirical rule.
First of all, we will find z-score for given sample score of 133 as z-score tells us a data point is how many standard deviation away from mean.
, where,
= Z-score,
= Sample score,
= Mean,
= Standard deviation.
We know that according to the empirical rule 68% of data lies within one standard deviation of mean, 95% of data lies within two standard deviation of mean and 99.7% of data lies within one standard deviation of mean.
Since 133 is 3 standard deviation above mean, so 0.3% lies above and below 3 standard deviation.
Since we need IQ scores above 133, so we will divide 0.3% by 2 as:
Therefore, 0.15% of IQ scores are greater than 133.
The required simplified value of b + g is 21.
Given that,
At a classroom costume party, the average age of the b-boys is g, and the average age of the g girls is b.
The average age of everyone at the party (all these boys and girls, plus their 42- year-old teacher) is b+g,
<h3>What is average?</h3>
The average of the values is the ratio of the total sum of values to the number of values.
Here,
The average age of the b-boys is g.
The average age of the g-girls is b.
The average age of everyone at the party (all these boys and girls, plus their 42-year-old teacher) is b+g,
Now,
average of n = 3 (b , g , b+g)
Average = g + b + 42 / 3
b + g = (b + g + 42 ) / 3
3b + 3g = b + g + 42
3b - b + 3g - g = 42
2b + 2g = 42
2 (b + g) = 42
b + g = 21
Thus, the required simplified value of b + g is 21.
Learn more about average here:
brainly.com/question/24057012
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Quadratic formula: x equals negative b plus or minus the square root of b squared minus 4 ac all over 2a
a=2 b=5 c=1
x=(-5+/5^2-4(2)(1))/2(2)
-5+/25-8/4
-5+/17/4
(-5+4.12)/4
-0.877/4
-0.219
x=(-5-/5^2-4(2)(1))/2(2)
-5-/25-8/4
-5-/17/4
(-5-4.12)/4
-9.12/4
-2.28
x=-0.219 or x=-2.28
