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n200080 [17]
2 years ago
10

Please do help help me with this i really need an answer I'll mark you brainliest

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
4 0

Please do help help me with this i really need an answer I'll mark you brainliest

NONSENSE answer will be REPORTED

Directions: IMAGINE that you were asked to give a review/critique of a work of art that you have seen in an art gallery or an event/performance that you have been to.

Write a 3-paragraph review/critique of your chosen work of art or event/performance.

Remember that you must only choose one.

Again, take note of all the guidelines in writing a review/critique. You may use a separate sheet of paper for your output.​

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A. the series is absolutely convergent.
Dovator [93]
\displaystyle\sum_{n=1}^\infty\left(1+\frac5n\right)^n

Notice that

\displaystyle\lim_{n\to\infty}\left(1+\frac5n\right)^n=e^5\neq0

which means the series is divergent. So if this is one of those "select all that apply" questions, then both (c) and (j) are the only choices that do.
7 0
3 years ago
Can someone help me with this?
alexandr1967 [171]
N = 4 + x? i think, im not really sure but im pretty sure it is
3 0
3 years ago
In parallelogram ABCD below, AC is a diagonal, the
Vinil7 [7]

Step-by-step explanation:

  • ABCD parallellogram
  • m< B = m< D = 40
  • in triangle ACD :

m < CAD = 180 - ( 40 + 57 ) = 83

7 0
2 years ago
Which shows one way to determine the factors of x^3 - 9x^2 + 5x - 45 by grouping ?
adoni [48]
You can group first two conjunctions and second two:
x^3 - 9x^2 + 5x - 45=(x^3-9x^2)+(5x-45).
In first brackets you have common x^2 and in second brackets common is 5:
(x^3-9x^2)+(5x-45)=x^2(x-9)+5(x-9)=(x-9)(x^2+5).
7 0
3 years ago
Solve for x<br><img src="https://tex.z-dn.net/?f=4%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%207x%20%2B%202" id="TexFormula1" title="4 {x
Alina [70]

\bf 4x^2=7x+2\implies 4x^2-7x-2=0\implies (4x+1)(x-2)=0 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4x\cdot x=\boxed{4x^2}~\hfill (1)(-2)=\boxed{-2}\hfill (4x\cdot -2)+(1\cdot x)=\boxed{-7x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 4x+1=0\implies 4x=-1\implies &x=-\cfrac{1}{4}\\[1em] x-2=0\implies &x=2 \end{cases}

7 0
2 years ago
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