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Kay [80]
3 years ago
8

Mr. Johansen is cutting construction paper for an art project. He has 24 students, and six pieces of construction paper. How muc

h paper will each student receive?
Mathematics
1 answer:
wariber [46]3 years ago
5 0

Answer: One- fourth piece of construction paper is received by each student.

Step-by-step explanation:

Given: Mr. Johansen is cutting construction paper for an art project.

The number of students in the art project = 24

The number of pieces of construction paper = 6 pieces

When  Mr. Johansen divides 6 pieces of construction paper in 24 students, the quantity of construction paper received by each student = \frac{6}{24}=\frac{1}{4}\ \tex{piece}

One- fourth piece of construction paper is received by each student.

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Kelly spends $63.90 on items for a party. She buys thank you cards that cost $5.40 (including tax). She also buys gift bags that
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$63.90 (total)

$5.40 (cards)

$11.70/per (bags)

$63.90 - $5.40 = $58.50

$58.50 / $11.70 = 5

She invited 5 guests (b).
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3 years ago
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Which is the equation of Line B?
notka56 [123]
  • Slope-Intercept Form: y = mx + b, with m = slope and b = y-intercept
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So firstly, to find the slope of this equation, plug the two points, (1,1) and (-3,2), into the slope formula and solve as such:

\frac{1-2}{1-(-3)}=-\frac{1}{4}

Next, plug either one of the points into the x and y coordinates to solve for b as such:

2=-\frac{1}{4}*-3+b\\2=\frac{3}{4}+b\\\frac{5}{4}=b

<u>Our final equation is y=-\frac{1}{4}x+\frac{5}{4} , or the third option.</u>

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3 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ&gt;0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\&#10;\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\&#10;\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\&#10;\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\&#10;\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\&#10;\mathsf{17\,sin^2\,\theta=1}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

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What two estimates is the quotient 345\8 between
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345/8 is the another one yes
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How i did? In livada sunt 12 mere am cules 6. Cate mera au ramas?
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Answer:

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Step-by-step explanation:

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