Using the frequency table, it is found that:
a) 99.2% of the group of eggs were less than 24.75 mm long.
b) 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
The frequency table gives the percentage of cuckoo bird eggs with the associated lengths.
- For example, 0.8% of eggs have lengths between 18.75 and 19.75 millimetres.
Item a:
- 0.8% of eggs were more than 24.75 mm.
Thus, 100 - 0.8 = 99.2% were less than 24.75 mm long.
Item b:
- 37.9% between 21.75 and 22.75 mm.
- 28.5% between 22.75 and 23.75 mm.
- 10.7% between 23.75 and 24.75 mm.
In total:
47.1% of the eggs are in these lengths, thus, 0.471 = 47.1% probability that one of the eggs selected at random was at least 21.75 mm long but less than 24.75 mm long.
A similar problem is given at brainly.com/question/24141790
How many batteries are in a pack?
You would take that number and divide it by 8.34. That would give you the price per battery. From there you can figure out how many batteries you can buy with only $3 and how much money would be left over.
3/4
Step-by-step explanation:
If you cut a whole pie into two you get two (2) ½ pieces
1 ÷ 2 = ½
When you cut the two ½ pieces into two you get four (4) ¼ pieces;
½ ÷ 2 = ¼
When you cut the four ¼ pieces into two you get 8 1/8 pieces;
¼ ÷ 2 = ¹/8
Therefore the whole pie at this point is made up of 8 ¹/8 pieces. When two (2) of these pieces are eaten we are left with 6 ¹/8 pieces;
8 – 2 = 6
The portion of the pie left therefore is;
6 * ¹/8 pieces
= ⁶/8
= ³/4
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The relevant trig relations are summarized by the mnemonic SOH CAH TOA. This means ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
Tan = Opposite/Adjacent
So, for each triangle, determine the relationships of the given sides to the given angle: adjacent, opposite, or hypotenuse. Then write and solve the equation using one of the above templates.
Answer:
9. 6k + 5 and 2k - 1.
10. 5√2 .
Step-by-step explanation:
9. Area = 12k^2 + 4k - 5
Factoring:
12k^2 - 6k + 10k - 5
= 6k(2k - 1) + 5(2k - 1)
= (6k + 5)(2k - 1)
So the required lengths are 6k + 5 and 2k - 1.
10. The ratio of a leg to the hypotenuse is 1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2
= 10 √2 / 2
= 5√2 .
