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3 years ago

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Louis borrowed money from his dad to buy a car. After 4 years, Louls finally repaid his dad for the cost of the car and an addit

ional $ 444 In Interest. If Louls's dad charged him 3% Interest, what was the price of the car? A $ 497 & $ 592 C $ 3,700 D. $ 5,328

1 answer:

Sophie [7]3 years ago

8 0

Sorry then dont know how to help

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Which function represents the exponential function f(x) = 3x after a vertical stretch by a factor of 8 and a reflection across t

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The answer should be letter A I believe correct me if I’m wrong.

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3 years ago

Write the equation of the given line in slope-intercept form.

gizmo_the_mogwai [7]

Answer:

y = 2x - 1

Step-by-step explanation:

Slope intercept form: y=mx+b

point a: (1, 1)

point b: (2, 3)

1. Find the slope of the equation

Equation for slope(mx): (y2- y1)/ (x2-x1)

(3-1)/(2-1)= 2

slope: 2

2. Pick any of the two point to find the "b" and plug in the coordinates of the point to find the y-intercept of the equation.

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3. Plug the answers you found above into the slope-intercept form

Overall equation:

y=2x - 1

7 0

3 years ago

0.6(4-2x)=20.5-(3x+10)

solong [7]

The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5

<u>Solution:</u>

Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )

We have to solve the above given equation for x.

Now, take the equation

$\rightarrow 0.6(4-2 x)=20.5-(3 x+10)$

We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction

On solving the brackets, we get

$\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10$

Now multiplication is given preference

$\rightarrow 2.4-1.2 x=10.5-3 x$

$\rightarrow 3 x-1.2 x=10.5-2.4$

Now subtraction is done

$\rightarrow 1.8 \mathrm{x}=8.1$

Now division is performed

$\rightarrow x=\frac{8.1}{1.8}=4.5$

Hence, the value of x is 4.5

5 0

3 years ago

Please help if you can pic attatched

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Subtract row 3 from row 1:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]$

Subtract row 3 from 7 times row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]$

Divide row 3 by 17:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 2 of row 3 from row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 6 of row 2 from row 1:

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

$C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]$

$C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]$

3 0

3 years ago

What is the area of the following figure?

kobusy [5.1K]

Answer:

where is the figure

Step-by-step explanation:

all ya gotta do is multiply the numbers together

3 0

3 years ago