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lutik1710 [3]
2 years ago
9

· Trees were planted on both sides of a 5km road at interval of 20m. How many trees were planted altogether?​

Mathematics
2 answers:
Alchen [17]2 years ago
7 0

Answer:

  502

Step-by-step explanation:

It depends on the arrangement.

If a tree is planted in the middle of each 20 m space, then you get one answer. If a tree is planted at the ends of each 20 m space, then you get a different answer.

Here, we will assume that a tree is planted at the ends of the road and every 20 m in between. Then the number planted on one side of the road is ...

  1 + (5000 m)/(20 m) = 251

And the number of trees planted on both sides of the road is ...

  2 × 251 = 502 . . . trees planted altogether

_____

<em>Additional comment</em>

If _ represents a 10 m space, the arrangements we're talking about above are ...

   _T_ . . . tree in the middle of the space

  T_ _ T . . . trees at the end of the space

Knowing that a tree requires room to spread out, we might choose the former arrangement. That would mean a total of 500 trees, rather than 502.

Pavlova-9 [17]2 years ago
6 0

Answer

10000 or 4000

Step-by-step explanation:

if its right mark brainlist?
please

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Use algebra to find the point at which the line h(x)=−(3/5)x+(7/5) intersects the line k(x)=(−8/3)x+(404/45).
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Answer: the point (3.667, 0.8)

Step-by-step explanation:

We want to find the point at which the lines:

h(x) = -(3/5)*x + (7/5)

and

k(x) = (-8/3)*x + (404/45)

If the lines intersect, then we must have:

h(x) = k(x)

if we write the functions we get:

-(3/5)*x + (7/5) = (-8/3)*x + (404/45)

Now we need to solve this for x.

-(3/5)*x + (8/3)*x = (404/45) - (7/5)

(8/3 - 3/5)*x = 404/45 - 63/45 = 341/45

(40/15 - 9/15)*x = 341/45

(31/15)*x = 341/45

x = (341/45)*(15/31) = 3.667

Now we can input this value of x in the functions to get the output.

h(3.667) = -(3/5)*3.667 + 7/5 = -0.8

Then the point where our points intersect is the point (3.667, 0.8)

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