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Lana71 [14]
3 years ago
10

In a blueprint for a house, the scale is 1 inch = 5 feet. In the blueprint, one room

Mathematics
1 answer:
Dimas [21]3 years ago
5 0

for each inch is 5 feet, so for each 0.5 aka 1/2 inch, it would be 2.5 inches

2in: 5+5=10ft

2.5in: 5+5+2.5=12.5ft

or just simply mutiply by 2

2(5)= 10ft

2.5 inches so 2.5(5)=12.5

The dimensions of the actual room are 10 feet by 12.5 feet

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X^2=-144 <br><br> Solve by factoring
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PLEASE ANSWER QUESTION
CaHeK987 [17]

Answer:

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8 0
2 years ago
A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po
Mariana [72]

Answer:

The work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

Step-by-step explanation:

The work is defined by:

W=\int dFdx (1)    

The force here will be the product between the volume and the kerosene weighing, so we have :

dF=\pi R^{2}dy*50

This force will be in-lbs.

Where R is the radius (3 feet)                    

Then using (1), we have:

W=\int \pi R^{2}dy*50(8-y)  

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)

W=450\pi \int_{0}^{8}dy(8-y)

W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)

W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})  

W=450\pi(8*8 -\frac{8^{2}}{2})

W=450\pi(64 -\frac{64}{2})

Therefore, the work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

I hope it helps you!  

6 0
3 years ago
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