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3 years ago

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Mathematics

2 answers:

Assoli18 [71]3 years ago

6 0

Step-by-step explanation:

Hi, there!!

According to the question, we should find the hypotenuse, adjacent, and opposite to the refrence angle A ,right.

so, let's simply work with it,

hypotenuse (h)= AC {side opposite to the 90° is always a hypotenuse}.

opposite (p)= BC { as the side opposite to the refrence angle is always perpendicular or opposite}

adjacent (b)= AB { as remaining side is always base or adjacent}

Hope it helps....

ycow [4]3 years ago

3 0

hypotenuse goes to the line across from the right angle. adjacent is the bottom one. lastly opposite is the left one.

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Is the sum of the areas of two smaller squares equal to the area of a large square if the side lengths of the squares are 8 feet

Ivanshal [37]

No, the sum of the areas of two smaller squares is not equal to the

area of a large square

Step-by-step explanation:

To solve this problem let us do these steps

1. Find the area of the larger square

2. Find the area of the two smaller squares

3. Add the areas of the two smaller squares

4. Compare between the sum of the areas of the 2 smaller squares

and the area of the larger square

The area of a square is s²

The length of the side of the larger square is 8 feet

∵ s = 8 feet

∴ Area of the larger square = (8)² = 64 feet²

The lengths of the sides of the smaller squares are 5 feet and 3 feet

∵ s = 5 feet

∴ The area of one of the smaller square = (5)² = 25 feet²

∵ s = 3 feet

∴ The area of the other smaller square = (3)² = 9 feet²

The sum of the areas of the two smaller squares = 25 + 9 = 34 feet²

∵ The area of the larger square is 64 feet²

∵ The sum of the areas of the two smaller squares is 34 feet²

∵ 64 ≠ 34

∴ The sum of the areas of two smaller squares is not equal to the

area of a large square

No, the sum of the areas of two smaller squares is not equal to the

area of a large square

Learn more:

You can learn more about the areas of figures in brainly.com/question/3306327

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4 0

3 years ago

Vanessa deposits $24,000 into each of two savings accounts. Account I earns 2. 4% interest compounded annually. Account II earns

ikadub [295]

The sum of the balances of these accounts at the end of 5 years is given by: Option B: $53,901.59 (approx)

<h3>How to calculate compound interest's amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:

$CI = P(1 +\dfrac{R}{100})^T - P$

The final amount becomes:

$A = CI + P\\A = P(1 +\dfrac{R}{100})^T$

<h3>How to calculate simple interest amount?</h3>

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

$I = \dfrac{P \times R \times T}{100}$

For the considered case, we're given that:

Initial amount in both accounts deposited = $24,000 = P
Type of interest: Compound interest in first account and simple interest in second account
Unit of time: Annually
Rate of interest = 2.4% annually = R
Total unit of time for which amount is to be calculated: 5 years = T

In first account, the final amount at the end of 5 years is evaluated as:

$A = 24000(1 + \dfrac{2.4}{100})^4 = 24000(1.024)^4 \approx 27021.59\: \rm (in \: dollars)$