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Dafna1 [17]
3 years ago
10

1

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Step-by-step explanation:

<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>According</em><em> </em><em>to the</em><em> </em><em>question</em><em>, </em><em>we</em><em> </em><em>should</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>hypotenuse</em><em>, </em><em>adjacent</em><em>, </em><em>and</em><em> </em><em>opposite</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>refrence</em><em> </em><em>angle</em><em> </em><em>A</em><em> </em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>let's</em><em> </em><em>simply</em><em> </em><em>work with it</em><em>,</em>

<em>hypotenuse</em><em> </em><em>(</em><em>h</em><em>)</em><em>=</em><em> </em><em>AC</em><em> </em><em> </em><em> </em><em>{</em><em>side</em><em> </em><em>opposite</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>9</em><em>0</em><em>°</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>a</em><em> </em><em>hypotenuse</em><em>}</em><em>.</em>

<em>opposite</em><em> </em><em>(</em><em>p</em><em>)</em><em>=</em><em> </em><em>BC</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>side</em><em> </em><em>opposite</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>refrence</em><em> </em><em>angle</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>perpendicular</em><em> </em><em>or</em><em> </em><em>opposite</em><em>}</em>

<em>adjacent</em><em> </em><em>(</em><em>b</em><em>)</em><em>=</em><em> </em><em>AB</em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>as</em><em> </em><em>remaining</em><em> </em><em>side</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>base</em><em> </em><em>or</em><em> </em><em>adjacent</em><em>}</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

ycow [4]3 years ago
3 0

hypotenuse goes to the line across from the right angle. adjacent is the bottom one. lastly opposite is the left one.

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