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Dafna1 [17]
3 years ago
10

1

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

Step-by-step explanation:

<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>According</em><em> </em><em>to the</em><em> </em><em>question</em><em>, </em><em>we</em><em> </em><em>should</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>hypotenuse</em><em>, </em><em>adjacent</em><em>, </em><em>and</em><em> </em><em>opposite</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>refrence</em><em> </em><em>angle</em><em> </em><em>A</em><em> </em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>let's</em><em> </em><em>simply</em><em> </em><em>work with it</em><em>,</em>

<em>hypotenuse</em><em> </em><em>(</em><em>h</em><em>)</em><em>=</em><em> </em><em>AC</em><em> </em><em> </em><em> </em><em>{</em><em>side</em><em> </em><em>opposite</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>9</em><em>0</em><em>°</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>a</em><em> </em><em>hypotenuse</em><em>}</em><em>.</em>

<em>opposite</em><em> </em><em>(</em><em>p</em><em>)</em><em>=</em><em> </em><em>BC</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>side</em><em> </em><em>opposite</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>refrence</em><em> </em><em>angle</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>perpendicular</em><em> </em><em>or</em><em> </em><em>opposite</em><em>}</em>

<em>adjacent</em><em> </em><em>(</em><em>b</em><em>)</em><em>=</em><em> </em><em>AB</em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>as</em><em> </em><em>remaining</em><em> </em><em>side</em><em> </em><em>is</em><em> </em><em>always</em><em> </em><em>base</em><em> </em><em>or</em><em> </em><em>adjacent</em><em>}</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

ycow [4]3 years ago
3 0

hypotenuse goes to the line across from the right angle. adjacent is the bottom one. lastly opposite is the left one.

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Given:

• Amount to save, A = $28,000

,

• Time, t = 6 years

,

• Interest rate, r = 5.3% ==> 0.053

,

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})

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FV is the future value = $28,000

r = 0.053

n = 4

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Thus, we have:

28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}

Let's solve for P.

We have:

\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\  \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\  \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\  \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}

Solving further:

28000=P(28.0384237)

Divide both sides by 28.0384237:

\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\  \\ 998.6=P \\  \\ P=998.6 \end{gathered}

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0
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Please do it in substitution method. Thanks.​
alina1380 [7]

Answer:  No solution

<u>Step-by-step explanation:</u>

x - 3y = 2   →     x = 3y + 2

2x - 6y = 6

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6y + 4 - 6y = 6            <em>distributed 2 into 3y+2</em>

        4        = 6           <em>simplified (6y - 6y = 0)</em>

4 = 6 is a FALSE statement so there is NO SOLUTION

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