A quadratic always has two solutions. They could be two real number solutions (the parabola crosses the x-axis in two places), one real number double solution (the parabola just touches the x-axis in one spot) to two complex (imaginary) solutions where the parabola doesn't cross the x-axis.
Please give me brainliest
Answer:
Option (3)
Step-by-step explanation:
In a right triangle,
Cosine rule →
Sine rule → 
In the given triangle,
By cosine rule,


Or cos(h°) = z ÷ x
Therefore, Option (3) will be the answer.
Answer:
0
Step-by-step explanation:
-10 + 10
-10 and 10 are additive inverses, so when we add them, it is equal to zero
-10 + 10 = 0
9514 1404 393
Answer:
![\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%260%262%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The system of equations can be written in standard form as ...
x + 0y = 2
0x +2y = 2
The augmented matrix representation of these is ...
![\left[\begin{array}{cc|c}1&0&2\\0&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%260%262%5C%5C0%262%262%5Cend%7Barray%7D%5Cright%5D)
First you find the area of the front face 1/2bh or in you case 10x12=120 1/2 of 120 is 60 next you multiply 60 by 20 to get 1,200 for the voulume