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Nuetrik [128]
3 years ago
9

Please help me with this

Mathematics
1 answer:
tankabanditka [31]3 years ago
3 0
I think this is what I found

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Please answer these I will give you all my points!
makvit [3.9K]
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ok so put it like that and it will be correct.............................................................................(long pause)........................................................................................................... (thinks) I think that the right answer.

5 0
3 years ago
As sum of money double in 20 years on simple interest . It will triple at the same rate in
11111nata11111 [884]
40 years and as rate is 5%
5 0
3 years ago
ANSWER ASAP!
morpeh [17]

Answer:

vvvvvcvv

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
3 years ago
The teacher passed out math books.The length is 10 inches and the width is 8 inches.What is the perimeter of each book?
miv72 [106K]

Answer:  The perimeter of each book is:  " 36 in. " .

__________________________________________________

Step-by-step explanation:

__________________________________________________

Note that the given units are all in "inches (in.)" .

Use the formula for the "perimeter of a rectangle" ;

{which happens to work for a "square" as well;

          since a "square" is a rectangle.}.

__________________________________________________

This is based on the assumption that the book is shaped like a

"rectangle"  (or "square" —which is a rectangle).

__________________________________________________

The formula for the Perimeter of a rectangle is:

  P = 2 L  + 2 w  ;

in which:

P =  the perimeter of the rectangle;

for which we shall solve;   [in "inches (in.)" ] ;

L =  the length of the rectangle = 10 in. (given) ;

w = the width of the rectangle = 8 in. (given) .

___________________________________________________

Now, plug the given values for the "length (L)" and the "width (w)" ;

 as follows:

___________________________________________________

    P = (2 * 10 in.)  +  (2 * 8 in.)  ;

    P = (20 in.)  +  (16 in.)  ;

   P = 36 in.

___________________________________________________

Answer:  The perimeter of each book is:  " 36 in. " .

___________________________________________________

Hope this helps!

    Best wishes in your academic pursuits

            — and within the "Brainly" community!

___________________________________________________

3 0
3 years ago
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