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uranmaximum [27]
2 years ago
14

Use the relationship between the angles in the figure to answer the question Which equation can be used to find the value of x?

Of x x+49-28 = 180
- 49 - 28 = 180
x + 49 + 28 = 180
x + 28 = 180​

Mathematics
1 answer:
dusya [7]2 years ago
3 0

Answer:

x + 49 + 28 = 180

Step-by-step explanation:

The angle adjacent to x on the left is vertically opposite 49° and is congruent.

The 3 angles then lie on a straight line and sum to 180° , that is

x + 49 + 28 = 180

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Determine if the equation below is a function with independent variable x. If so, find the domain. If not, find a value of x to
Andre45 [30]

Answer:

No because it contains points (3,4) and (3,-4).  You cannot have a x assigned to more than one y-value if you want it to be a function.

Step-by-step explanation:

A function has one output per input.

If we are trying to determine if the given is a function of x, then x is the input.

However I can get two outputs from plugging in x=3.

3^2+y^2=25

9+y^2=25

Subtract 9 on both sides:

y^2=25-9

y^2=16

Take the square root of both sides:

y=\pm \sqrt{16}

y=\pm 4.

So input x=3 yields y=4 and y=-4.

Since this input has more than one output then the given is not a function of x.

----Also!

If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:

(\pm 5)^2+y^2=25

25+y^2=25

Subtract 25 on both sides:

y^2=25-25

Simplify:

y^2=0

There is only one value y such that when you square it gives you 0. That is 0.

x=5 only gives y=0 and x=-5 only gives y=0.

There is no circle, unless it is a circle with radius 0 which means it really wouldn't be a circle, that is a function.

8 0
3 years ago
Jijijjjjijij the question thingy
statuscvo [17]

Answer:

yes sir and thank u very good sir I am not sure how to get a new job

8 0
3 years ago
Read 2 more answers
What is Index Law 2?<br> please give definition
ioda

LAW 2: The second law of indices tells us that when dividing a number with an exponent by the same number with an exponent, we have to subtract the powers. In algebraic form, this rule is as follows . The a represents the number that is divided by itself and m and n represent the powers.

6 0
3 years ago
Read 2 more answers
a 5th grade volleyball team scored 32 points in one game. of those points 2/8 were scored in the second half. how many points we
Degger [83]

Answer:

Number of points scored in the first half of the match is 24 points.

Step-by-step explanation:

Total point scored in the volleyball game = 32

Let us assume the points scored in the first half = m

and the point scored on the second half = 2/8 of (Total points)

= \frac{2}{8}  \times  32  = 8

⇒ The number of points s cored in the second - half  =  8 points

Now, Points in FIRST half+ Points in SECOND  half=  Total Points

⇒ m+ 8 = 32

or, m  = 32 - 8 =  24

⇒ m = 24

Hence, the number of points scored in the first half is 24 points.

4 0
3 years ago
If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0
3 years ago
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