Can somebody explain how you can tell whether a histogram has an outlier.

1 answer:

6 0

An outlier is an observation that lies outside the overall pattern of a distribution. Usually, the presence of an outlier indicates some sort of problem. This can be a case which does not fit the model under study, or an error in measurement.hope this helps

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"Data from the World Health Organization in 2013 were used to predict the life expectancy of men in a country from the life expe

marshall27 [118]

Answer:

The predicted life expectancy of men in a country in which the life expectancy of women is 70 years is 65.33 years.

Step-by-step explanation:

The least square regression line is used to predict the value of the dependent variable from an independent variable.

The general form of a least square regression line is:

$\hat y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

The regression line to predict the life expectancy of men in a country from the life expectancy of women in that country is:

$\hat y=3.73 +0.88 x$

Compute the life expectancy of men in a country in which the life expectancy of women is 70 years as follows:

$\hat y=3.73 +0.88 x$

$=3.73 +(0.88\times 70)\\=3.73+61.6\\=65.33$

Thus, the predicted life expectancy of men in a country in which the life expectancy of women is 70 years is 65.33 years.

6 0

3 years ago

If f(x)=1/9x-2 , what is f–1(x)?

Anna71 [15]

Lets get started :)

f(x) = $\frac{1}{9}x$ - 2
y = $\frac{1}{9}x$ - 2
This is the original equation, and now we have to find the inverse.

When finding the inverse, just flip the variables, x as y and y as x

f ⁻¹(x)
↓
x = $\frac{1}{9}y$ - 2
We have to isolate y as it is our f ⁻¹(x)

Take 2 to the other side { When you see subtraction, you do addition }
x + 2 = $\frac{1}{9} y$

Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y

f ⁻¹ (x) = 9x + 18

7 0

2 years ago

....................................Graph y=−x−2.

pychu [463]

See attached photo for the graph