The probability of rolling a sum of 5 on a standard pair of six sided dice is 1/9.
According to the given question.
A standard pair of dice is rolled.
So, the sample sapce for rolling a pair of dice = {(1,1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4),(5, 5),(5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
⇒ Total number of outcomes = 36
And, the outcomes for getting a sum of five on a sandard pair of six sided dice = {(2, 3), (3, 2), (4, 1), (1, 4)}
⇒ Total number of favorable outcomes = 4
As we know that " probability is the ratio of total number of favorable outcomes to the total number of outcomes".
Therefore,
The probability of rolling a sum of 5 on a standard pair of six-sided dice
= 4/36
= 1/9
Hence, the probability of rolling a sum of 5 on a standard pair of six sided dice is 1/9.
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