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jekas [21]
2 years ago
8

The largest doll is 7 inches tall. Each of the other dolls is 1 inch shorter than the next larger doll. Complete the table that

compares the surface areas and the volumes of the seven dolls.
50 PTS!!!!!!!
Mathematics
2 answers:
ELEN [110]2 years ago
7 0
EXPLANATION:

as it is written, the biggest doll is 7 inches tall, and they told you to decrease 1 inch after every doll, so therefore you can decrease 1 inch 7 times; so the answer is 7,6,5,4,3,2,1
kvv77 [185]2 years ago
6 0

Answer:

7,6,5,4,3,2,1,

Step-by-step explanation:

this is in chronological order

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What is the circumference of a circle that has a radius of 17 cm
Effectus [21]

Answer:

106.8

Step-by-step explanation:

17 * 2 = 34

34 * pi = 106.8

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3 years ago
List the domain of the following points from least to greatest: (-2, 4) (-6,8) (3,6) (5,15) (-1, 4)
nasty-shy [4]

Answer:

Domain = {-6, -2, -1, 3, 5}

Step-by-step explanation:

The domain represents the input or x values of a given relation.

In the given set of ordered pairs: (-2, 4) (-6,8) (3,6) (5,15) (-1, 4)

Domain (input/x values) = {-6, -2, -1, 3, 5}

Range (output/y values) = {4, 6, 8, 14}

3 0
3 years ago
The following table represents the sample space of rolling two number cubes.
alex41 [277]
We just need to count the number of outcomes that have exactly one even number. The total number of outcomes is 36. We see that from the first row, the number of outcomes that qualify are 3: 1-2, 1-4, 1-6 (out of the 6 total outcomes). For the 2nd row, again there are 3: 2-1, 2-3, 2-5. It is obvious by now that for any row, whether the number is even or odd, there are 3 outcomes on that row that correspond to rolling exactly one even number. Hence, there are in total 6*3=18 favorable outcomes.
4 0
2 years ago
Read 2 more answers
What is the surface area in square inches of the prism​
Lerok [7]

Answer: the answer is 25

Step-by-step explanation:

7 0
2 years ago
The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan
Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

\mu = E(X) = np = 100*0.23 = 23

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 23}{4.1}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0
3 years ago
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