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Paraphin [41]
3 years ago
6

Please somone tell me the right answer

Mathematics
1 answer:
algol [13]3 years ago
3 0

Answer:

40%

the whole this is 250% nod nod

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The table shows information about the numbers of hours 30 children spent on their tablets one evening. a) find the class interva
Bogdan [553]

Answer:

a) 20<h≤30.

b) 26.17 hrs

Step-by-step explanation:

The missing table is shown in attachment.

Part a)

We need to find the class interval that contains the median.

The total frequency is

\sum \: f = 30

The median class corresponds to half

\frac{1}{2}  \sum \: f ^{th}  -  -  - value

That is the 15th value.

We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.

2+8+9=19

This corresponds to the class interval 20<h≤30.

Adding from the bottom also gives the same result.

Therefore the median class is 20<h≤30.

b) Since this is a grouped data we use the midpoint to represent the class.

The median is given by :

\frac{\sum \: fx}{ \sum\: f}

=  \frac{5 \times 3 + 15\times 8 + 25 \times 9 + 35 \times 7 + 45 \times 4}{30}

=  \frac{785}{30}

= 26.17

8 0
3 years ago
Read 2 more answers
I need help with this
Salsk061 [2.6K]

Answer:

cool dude

Step-by-step explanation:

7 0
3 years ago
Answer for 2,3,4 help pls thanks
Lemur [1.5K]

(90 \times 15) \div 9 =  \: is \: your \: answer

Step-by-step explanation:

1. B is true

2 . I don't know

3.

4 0
3 years ago
Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4
Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

p(x)= -x+4x^2+Cx^3-8x^4 \\  \\  \because \: given \: polynmial \: has \: zero \: at \: \\x =  \frac{1}{4}  \\  \\  \implies \: p\bigg(\frac{1}{4}  \bigg) = 0...(1) \\  \\ plug \: x = \frac{1}{4} \:  in \: p(x) \: we \: find \\  \\ p \bigg(\frac{1}{4}  \bigg)  =  - \frac{1}{4} + 4  {\bigg(\frac{1}{4} \bigg)}^{2}  + c  {\bigg(\frac{1}{4} \bigg)}^{3}  - 8  {\bigg(\frac{1}{4} \bigg)}^{4}  \\  \\ 0 = - \frac{1}{4} + \cancel 4 \times   {\frac{1}{\cancel{16} } }  + c  {\bigg(\frac{1}{64} \bigg)}  - \cancel 8  \times  \frac{1}{\cancel{256} }  \\  \\0 =\cancel{ - \frac{1}{4}} + \cancel  {{\frac{1}{4} }}  + c  {\bigg(\frac{1}{64} \bigg)}  -  \times  \frac{1}{32}  \\  \\0 =  c  {\bigg(\frac{1}{64} \bigg)}  -  \frac{1}{32}  \\  \\c  {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32}   \\  \\ c = \frac{1}{32}   \times 64 \\  \\ c = 2

5 0
3 years ago
Which answer is equal to the quotient in the expression below? (2x3 - x2) (x2)
serg [7]

(2x3 - x2) / (x2)

= 2x^3/x^2 - x^2/x^2

=2x - 1

answer

2x - 1

4 0
3 years ago
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