Answer:
(7, ∞)
Step-by-step explanation:
Because x does not equal 7 as well, brackets won't be used here.
Because x can be any number greater than 7, this means the domain includes positive ∞.
The value of the expression is 
Explanation:
The expression is ![$2 \times[(12+2) \times 5]+\frac{3}{2}$](https://tex.z-dn.net/?f=%242%20%5Ctimes%5B%2812%2B2%29%20%5Ctimes%205%5D%2B%5Cfrac%7B3%7D%7B2%7D%24)
The value of the expression can be determined using the rule PEMDAS.
According to the PEMDAS rule, first we need to perform the operation which is within the parenthesis.
Thus, the expression becomes,

Multiplying the values within parenthesis, we have,

Using PEMDAS, we need to multiply the numbers.

Again using PEMDAS rule, divide the number,

Finally, using PEMDAS, let us add the values, we have,

Thus, the value of the expression is 
A hexagon can be considered to be 6 triangles with a common vertex.
Area of 1 of the triangle = 1/2 * 2 * side length
Area of whole hexagon is 6 times this.
9514 1404 393
Answer:
300
Step-by-step explanation:
There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students <em>in a particular order</em>.
Since we don't care about the order, we can divide this number by the number of ways two students can be ordered: AB or BA, 2 ways.
600/2 = 300
There are 300 ways to pick a combination of two students from 25.
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<em>Additional comments</em>
This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.
"n choose k" can be written nCk or C(n, k)
The function is a ratio of factorials:
nCk = n!/(k!(n-k)!)
If you can typeset this, it is written ...

This is different from the formula for the number of <em>permutations</em> of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.