Can somebody please help me I will mark u brilliant
2 answers:
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Answer:
I attached a picture of the completed picture below.
The values given to you in the picture are shown in pink
Use those values to fill in the rest, which are shown in blue.
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; in triangle ΔFGH;
Segment = 14
Segment
= 14
Segment = 27
Segment
= 19
Segment = 19
Segment
= 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and
= 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and
= 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅
by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ =
= 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°