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Fed [463]
2 years ago
12

1/2 of a bowl of cereal is divided equally between 4 bowls. how much cereal is in each bowl

Mathematics
2 answers:
Ksju [112]2 years ago
7 0

Answer:

1/8  

Step-by-step explanation:

1/2 / 4

= 1/2 * 1/4

= 1/8.

Lubov Fominskaja [6]2 years ago
5 1

Answer:

1/16 of the cereal is in each bowl

Step-by-step explanation:

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Carmine paid an electrician x dollars per hour for a 5-hour job plus $70 for parts. The total charge was $320. Which equation ca
pentagon [3]
Division is the answer
4 0
3 years ago
Write the quadratic equation whose roots are 4 and 5, and whose leading coefficient is 4.
Umnica [9.8K]

Answer:

<u>Answer</u><u>:</u><u> </u><u>4</u><u>x</u><u>²</u><u> </u><u>-</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>0</u><u> </u>

Step-by-step explanation:

• General quadratic equation:

{ \rm{ {x}^{2}  - (sum \: of \: roots)x + (product \: of \: roots) }}

• sum of roots → 4 + 5 = 9

• product of roots → 4 × 5 = 20

• substitute:

{ \boxed{ \rm{4 {x}^{2}  - 9x + 20 }}}

3 0
3 years ago
Enter the ratio as a fraction in lowest terms<br><br> 30 minutes to 27 minutes
vampirchik [111]

Step-by-step explanation:

ratio will be

30/27

= 10/9

=10:9

7 0
3 years ago
Read 2 more answers
Suppose a certain series of gymnastic moves takes 35 seconds to complete. If a gymnast does that series seven times in a row, ho
Sophie [7]

Answer:

  4 minutes 5 seconds

Step-by-step explanation:

Without additional information, we have to assume that one sequence can begin immediately after another, and that each takes the same amount of time. The total time for 7 sequences is 7 times the time for one sequence.

  7 × 35 seconds = 245 seconds = 4 minutes 5 seconds

__

There are 60 seconds in a minute.

5 0
3 years ago
Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

3 0
3 years ago
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