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1 year ago

Please help with this math problem!! IT'S DUE TONIGHT AT 11:59PM!! NO LINKS PLEASE!! :)

Mathematics

2 answers:

Anika [276]1 year ago

7 0

Answer:

$c = \: \: 0 \: \: \: 1 \: \: 2 \: \: 3 \: \: 5 \: \: 7$

Step-by-step explanation:

check this pls

but im not sure;-)

pa heart and 5 star

if check po

almond37 [142]1 year ago

4 0

Answer:

$C= -2p+5, \text{where slope is} ~-2.$

Step by step explanation:

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2 years ago

Which graph shows the solution to the following equation 2x-5/x^2 = -4

notsponge [240]

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Step-by-step explanation:

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2 years ago

find the equation of the line that is parallel to the line Y equals 3X -6 and passes through the points (1 -8). Write the equa

AlladinOne [14]

<h3>hello!</h3>

=====================================================

Parallel lines have the same slope.

So if the given line has a slope of 3, then the line parallel to it has the same slope (3)

Now, let's write the equation of the line in Point-Slope Form.

Remember, point-slope form looks like so:-

$\bigstar{\underline{\boxed{\pmb{y-y1=m(x-x1)}}}$

Where

y₁ is the y-coordinate of the point that the line passes through

m is the slope

x₁ is the x-coordinate of the point that the line passes through

In this case,

y₁ is equal to -8

m is equal to 3

x₁ is equal to 1

Plug in the values:

$\longrightarrow\sf{y-(-8)=3(x-1)}$

Simplify:

$\longrightarrow\sf{y+8=3(x-1)}$

and we're done!

=========================================================

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)

4 0

2 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago