Assume L=1.5W, where W=width, L= Length of the triangle.
Therefore,
Perimeter (P) = 2(W+L) = 2(W+1.5W) = 2(2.5W) = 5W=20 => W=20/5 = 4 in
Then, L=1.5W = 1.5*4 = 6 in
Area, A= L*W = 6*4 = 24 in^2
Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
Answer:
pretty sure its -2,3 :)
Step-by-step explanation:
Answer:
(2, - 6 )
Step-by-step explanation:
Given the 2 equations
x = 
y + 5 → (1)
2x + 3y = - 14 → (2)
Substitute x = y + 5 into (2)
2( y + 5 ) + 3y = - 14 ← distribute and simplify left side
y + 10 + 3y = - 14
4y + 10 = - 14 ( subtract 10 from both sides )
4y = - 24 ( divide both sides by 4 )
y = - 6
Substitute y = - 6 into (1) for corresponding value of x
x = (0.5 × - 6 ) + 5 = - 3 + 5 = 2
Solution is (2, - 6 )
