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3 years ago

What's the domain of this function? I typed [-4,5] but it says it's wrong!!! Please help!!!! It's due today!

Mathematics

2 answers:

Ksivusya [100]3 years ago

6 0

The x in this function cannot equal to -4, then we need to use ( to indicate that. This, the answer should be (-4, 2]. If you haven’t cover that yet, just try (-4, 2) or [-4, 2]

Whitepunk [10]3 years ago

3 0

Answer:

negative infinity to positive infinity

Step-by-step explanation:

The graph keeps going forever on both ends.

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4 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago

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Komok [63]

Answer:

I believe it's the one on the bottom left

Step-by-step explanation:

I'm still taking my test so I'll come back later to tell you if it's correct.

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3 years ago

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3 years ago

Read 2 more answers