Answer:
Yes. The data provide enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.
P-value=P(t>2.84)=0.0024
Step-by-step explanation:
Hypothesis test on the population mean.
The claim is that the mean weight of one-year-old boys is greater than 25 pounds.
Then, the null and alternative hypothesis are:
![H_0: \mu=25\\\\H_a:\mu>25](https://tex.z-dn.net/?f=H_0%3A%20%5Cmu%3D25%5C%5C%5C%5CH_a%3A%5Cmu%3E25)
The significance level is α=0.05.
The sample size is n=354. The sample mean is 25.8 pounds and the sample standard deviation is 5.3 pounds. As the population standard deviation is estimated from the sample standard deviation, we will use a t-statistic.
The degrees of freedom are:
![df=n-1=354-1=353](https://tex.z-dn.net/?f=df%3Dn-1%3D354-1%3D353)
The t-statistic is:
![t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{25.8-25}{5.3/\sqrt{354}}=\dfrac{0.8}{0.2817}=2.84](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B%5Cbar%20x-%5Cmu%7D%7Bs%2F%5Csqrt%7Bn%7D%7D%3D%5Cdfrac%7B25.8-25%7D%7B5.3%2F%5Csqrt%7B354%7D%7D%3D%5Cdfrac%7B0.8%7D%7B0.2817%7D%3D2.84)
For a right tailed test and 353 degrees of freedom, the P-value is:
![P-value=P(t>2.84)=0.0024](https://tex.z-dn.net/?f=P-value%3DP%28t%3E2.84%29%3D0.0024)
As the P-value is smaller than the significance level, the effect is significant and the null hypothesis is rejected.
There is enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.
Answer:
B. y = 1.3 + 2
Step-by-step explanation:
The slope is positive, and the y intercept is at positive 2.
Answer:
x = 21
Step-by-step explanation:
Based on the inscribed angle theorem, we would have:
120° = 2(3x - 3)°
Solve for x
120 = 2*3x - 2*3
120 = 6x - 6
Add 6 to both sides
120 + 6 = 6x
126 = 6x
Divide both sides by 6
126/6 = x
21 = x
x = 21
Answer:
Option 3 - ![y=-6x+28](https://tex.z-dn.net/?f=y%3D-6x%2B28)
Step-by-step explanation:
Given : Perpendicular to the line
; containing the point (4,4).
To Find : An equation for the line with the given properties ?
Solution :
We know that,
When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.
Slope of the equation ![x - 6y = 8](https://tex.z-dn.net/?f=x%20-%206y%20%3D%208)
Converting into slope form
,
Where m is the slope.
![y=\frac{x-8}{6}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx-8%7D%7B6%7D)
![y=\frac{x}{6}-\frac{8}{6}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bx%7D%7B6%7D-%5Cfrac%7B8%7D%7B6%7D)
The slope of the equation is ![m=\frac{1}{6}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B1%7D%7B6%7D)
The slope of the perpendicular equation is ![m_1=-\frac{1}{m}](https://tex.z-dn.net/?f=m_1%3D-%5Cfrac%7B1%7D%7Bm%7D)
The required slope is ![m_1=-\frac{1}{\frac{1}{6}}](https://tex.z-dn.net/?f=m_1%3D-%5Cfrac%7B1%7D%7B%5Cfrac%7B1%7D%7B6%7D%7D)
![m_1=-6](https://tex.z-dn.net/?f=m_1%3D-6)
The required equation is ![y=-6x+c](https://tex.z-dn.net/?f=y%3D-6x%2Bc)
Substitute point (x,y)=(4,4)
![4=-6(4)+c](https://tex.z-dn.net/?f=4%3D-6%284%29%2Bc)
![4=-24+c](https://tex.z-dn.net/?f=4%3D-24%2Bc)
![c=28](https://tex.z-dn.net/?f=c%3D28)
Substitute back in equation,
![y=-6x+28](https://tex.z-dn.net/?f=y%3D-6x%2B28)
Therefore, The required equation for the line is ![y=-6x+28](https://tex.z-dn.net/?f=y%3D-6x%2B28)
So, Option 3 is correct.