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Hoochie [10]
2 years ago
8

What is the value of x in the solution to this system of equations?

Mathematics
1 answer:
8_murik_8 [283]2 years ago
8 0

Step-by-step explanation:

the answer should be a I think

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Find the standard equation for the circle having the given center and radius.
RoseWind [281]

\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{0}{h}~~,~~\underset{0}{k})}\qquad \stackrel{radius}{\underset{7}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - 0 ~~ )^2 ~~ + ~~ ( ~~ y-0 ~~ )^2~~ = ~~7^2\implies x^2+y^2=49

7 0
2 years ago
Multiply eight and eighty-eight hundredths by two and three tenths
zimovet [89]

Answer:

20.424

Step-by-step explanation:

Given words can be written as

Eight and eighty-eight hundredths = (8+\frac{88}{100})

                                                            = \frac{800+88}{100}

                                                            = 8.88

Two and three tenth = (2+\frac{3}{10})

                                   =  \frac{20+3}{10}

                                   =  2.3

Now multiply them

i.e 8.88 × 2.3 = 20.424

So 20.424 is the Answer

7 0
3 years ago
Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?
Svet_ta [14]

Answer:

1.83 times

Step-by-step explanation:

Take the distance biked divided by the distance run.

2 3/4 / 1.5 = 1.83 times.

This means that Alex biked 1.83 times more than the distance she ran.

If this answer is correct, please make me Brainliest!

4 0
3 years ago
In Terry's hometown, the probability of snow on Saturday is approximately 0.07. Which of the following
Dmitry [639]

Answer:

c

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

the probability it would snow is 0.07 or 7%. this is quite low. so, it is unlikely that it would snow

3 0
3 years ago
Read 2 more answers
(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
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