Express as a trinomial (2x+8)(x-3)

Mathematics

2 answers:

Luden [163]3 years ago

8 0

Answer:

$\huge\boxed{(2x+8)(x-3)=2x^2+2x-24}$

Step-by-step explanation:

$\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x+8)(x-3)=(2x)(x)+(2x)(-3)+(8)(x)+(8)(-3)\\\\=2x^2-6x+8x-24\qquad\text{combine like terms}\\\\=2x^2+(-6x+8x)-24\\\\=2x^2+2x-24$

LuckyWell [14K]3 years ago

8 0

Answer:

2x^2+2x-24

Step-by-step explanation:

when you see two parentheses, you should first think : FOIL!

you take the First terms in each of the parentheses which is 2x and x and multiply them. (2x^2)

then you take the Outer terms in the parenthesis which is 2x and -3 and multiply them. (-6x)

then you take the Inside terms which is +8 and x and multiply them. (+8x)

lastly, you take the Last terms which is +8 and -3 and multiply them. (-24)

you should get this : 2x^2-6x+8x-24. combine like terms and there's your answer!

i also advise you to write down all your terms until you are familiar with this foil stuff. don't be ashamed if you need to write them down! you'll get the hang of it! :)

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Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel

nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

$\theta=\frac{\pi}{3}$

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be= $r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j$

By using $cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Force along the plane will be= $\mid F_x\mid=F\cdot r$

Force along the plane will be = $\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3$ N