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IrinaK [193]
2 years ago
8

Ruby had 9 times as many beads as Sam.

Mathematics
1 answer:
Hatshy [7]2 years ago
8 0

Answer:

If sam had x accounts, then ruby ​​had 9x then:

X + 9X = 120

10X = 120

X = 120/10

X = 12

If ruby ​​had 9x then she had:

9(12) = 108

And Sam:

12

108 - 12 = 96

Ruby had 96 more accounts than Sam

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

5 0
3 years ago
For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.
Flauer [41]

 

\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\

.

\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276

.

\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}    

 

 

8 0
3 years ago
NEED HELP ASAP!! PLEASE HELP!
Darya [45]
The second one is correct
7 0
3 years ago
The perimeter of the triangle shown is 412 meters. Find the length of each side.
Fudgin [204]

Answer:

x meters= 35

5x meters= 175

6x - 8 = 202

Step-by-step explanation:

x + 5x + (6x - 8)= 412

12x - 8= 412

12x = 412 + 8

12x = 420

x= 35

5x = 35× 5

= 175

6x - 8= 6(35) - 8

= 210 - 8

= 202

7 0
2 years ago
1 QUESTION. PLEASE HELP. VOLUME GEOMETRY QUESTION.
mina [271]
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Hope this helps! I apologize for my long response
3 0
3 years ago
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