How do I evaluate each using the values given q- m/2; use m=2, and q=6

jolli1 [7]

The first one is 37 .Second one is 25+9 and the 3 on top of the 9 (sum means add and cubed means 3 you dont add them tho) third one is 3 all you do is divide. Fourth one is 20

6 0

3 years ago

Pollution of the rivers in the United States has been a problem for many years. Consider the following events: a: the river is p

vampirchik [111]

Answer:

The answer is below

Step-by-step explanation:

P(A') = 1 - P(A) = 1 - 0.3 = 0.7

P(B'/A) = 1 - P(B/A) = 1 - 0.75 - 0.25

P(B/A') = 0.2, P(B'/A') = 1 - 0.2 = 0/8

P(C|A∩B) = 0.20,

P(C|A'∩B) = 0.15,

P(C|A∩B') = 0.80, and

P(C|A'∩B') = 0.90.

A) From conditional probability;

P(B/A) = P(B ∩ A) / P(A)

P(B∩A) = P(B/A) × P(A) = 0.75 × 0.3 = 0.225

P(C/A∩B) = P(A∩B∩C)/P(A∩B)

P(A∩B∩C) = P(C/A∩B) × P(A∩B)

P(A∩B∩C) = 0.2 ×0.225 = 0.045

B) P(A∩B∩C) = P(A) × P(B/A) × P(C/A∩B)

P(B'∩C) = P(A∩(B'∩C)) + P((A'∩B')∩C)

P(B'∩C) = P(A) × P(B'/A) × P(C/A∩B') + P(A') × P(B'/A') × P(C/A'∩B')

P(B'∩C) = 0.3 × 0.25 × 0.8 + (0.7 × 0.8 × 0.9) = 0.06 + 0.504 = 0.564

C) P(C) = P(A∩B∩C) + P(A'∩B∩C) + P(A∩B'∩C) + P(A'∩B'∩C)

P(A'∩B∩C) = P(A') × P(B/A') × P(C/A'∩B) = 0.7 × 0.2 × 0.15 = 0.021

P(A∩B'∩C) = P(A) × P(B'/A) × P(C/A∩B') = 0.3 × 0.25 × 0.8 = 0.06

P(A'∩B'∩C) = P(A') × P(B'/A') × P(C/A'∩B') = 0.7 × 0.8 × 0.9 = 0.504

P(C) = P(A∩B∩C) + P(A'∩B∩C) + P(A∩B'∩C) + P(A'∩B'∩C) = 0.045 + 0.021 + 0.06 + 0.504 = 0.63

D) P(A/B'∩C) = P(A∩B'∩C)/P(B'∩C)

P(A/B'∩C) = 0.06 / 0.564 = 0.106

6 0

4 years ago

A large serving of soup from a take-out restaurant is 4/5 liter. The restaurant has 3 liters of soup. The diagram models the num

shutvik [7]

Answer:

The answer is 2 and 2/5 i hope this can help.

Step-by-step explanation:

8 0

3 years ago

The Brooklyn District Attorney's office analyzed the leading (leftmost) digits of check amounts in order to identify fraud. The

iragen [17]

Answer:

The expected number of checks among 784 that should have a leading digit of "1" is 236.

Step-by-step explanation:

Let X = number of checks that has the leading digit as "1".

The probability of a check having a leading digit as "1" is, p = 0.301.

The number of checks issued by a suspected company is, n = 784.

A check is having a leading digit "1" is independent of other checks.

A randomly selected check either has the leading digit 1 or not.

The success of the experiment is defined as, a check having the digit "1" as the leading digit.

The random variable X follows a Binomial distribution with parameters n = 784 and p = 0.301.

The expected value of a random variable is the average number of times the random variable occurs.

The formula to compute the expected value of a Binomial distribution is:

$E(X)=n\times p$

Compute the expected value of X as follows:

$E(X)=n\times p\\$

$=784\times 0.301\\=235.984\\\approx236$

Thus, the expected number of checks among 784 that should have a leading digit of "1" is 236.

7 0

4 years ago

If Devon took 20 min to drive 24 km, what was his R.O.C.? Answer in decimals.

kondor19780726 [428]

Answer:

1.2 km/min

Step-by-step explanation:

ROC? rate of change? if not rate of change than my answer may not be correct

24km/20min = 1.2 km/min

24km/20min * 60min/1 hr= (24*60)/20=120 km/hr

5 0

3 years ago