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Andru [333]
3 years ago
5

Solve the following system of equations algebraically: y = x^2+7x−4 y = −x−4

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
7 0
Y = x² + 7x - 4
y = -x - 4

x² + 7x - 4 = -x - 4
      + x       + x
x² + 8x - 4 = -4
           + 4  + 4
     x² + 8x = 0
x(x) + x(8) = 0
    x(x + 8) = 0
x = 0  or  x + 8 = 0
                   - 8  - 8
                     x = -8

      y = -x - 4
      y = -0 - 4
      y = 0 - 4
      y = -4
(x, y) = (0, -4)
         or
       y = -x - 4
       y = -(-8) - 4
       y = 8 - 4
       y = 4
 (x, y) = (-8, 4)

The solutions are (0, -4) and (8, -4).
rodikova [14]3 years ago
5 0
Y=x²+7x-4
y=-x-4

We can solve this system of equation by equalization method.
x²+7x-4=-x-4
x²+7x+x-4+4=0
x²+8x=0
x(x+8)=0
we have two linear equations :
x=0                                ⇒  x=0        ⇒  y=-x-4=-0-4=-4
(x+8)=0                         ⇒  x=-8      ⇒  y=-x-4=-(-8)-4=8-4=4
 
We have two solutions:
solution₁:  x=0;  y=-4
solution₂:  x=-8; y=4
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Step-by-step explanation:

First, start out with the parent function:

y = b^{x}

Now, we look at the transformations, and make the equation.

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<u>Then, when you plug in 1, you get 3, then 3 - 4 equals -1. This matches up with the graph.</u>

<u />

This is the answer:

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