The slope of the line that passes throught (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given
(-4,3) and (-8,6)
slop=(6-3)/(-8-(-4))=(3)/(-8+4)=3/-4=-3/4
slope is -3/4
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
Step-by-step explanation:
If you don't know how to divide polynomials then I can help with that too or you can just search it up
The answer is 2 first you add then multiple
Answer:
4
Step-by-step explanation:
It's easy because 4-4=0 and anything divided by zero is zero.