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kogti [31]
3 years ago
14

Simplify the expression below. (–7x + 4) – (2x – 8)

Mathematics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

- 9x + 12

Step-by-step explanation:

Given

(- 7x + 4) - (2x - 8) ← distribute parenthesis by 1 and - 1

= - 7x + 4 - 2x + 8 ← collect like terms

= - 9x + 12

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GenaCL600 [577]

i would pick number C) since i think it would be the correct answer

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3rd question, I’m sorry guys but I was sick that’s why I didn’t attend school and the teacher said if I didn’t submit it by 5 ho
aniked [119]

Answer:

21.  ΔUYZ <u>Obtuse</u>

22. ΔBCD <u>Right or Rectangle</u>

23. ΔADB <u>Acute</u>

24. ΔUXZ <u>Acute</u>

25. ΔUWZ <u>Right or Rectangle</u>

26. ΔUXY <u>Equiangular and acute</u>

Step-by-step explanation:

We need to classify each triangle by its angles.

Acute: They have 3 acute angles (less than 90 degrees).

Rectangle: The inner angle A is straight (90 degrees) and the other 2 angles are sharp. The sides that form the right angle are called legs (c and b), the other side hypotenuse.

Obtuse: The inner angle A is obtuse (more than 90 degrees). The other 2 angles are acute.

ΔUYZ Obtuse  The inner angle Y is obtuse (more than 90°).

ΔBCD Right or Rectangle The inner angle C is straight (90°).

ΔADB Acute It has 3 acute angles (less than 90°).

ΔUXZ Acute  It has 3 acute angles (less than 90°).

ΔUWZ Right or Rectangle The inner angle W is straight (90°).

ΔUXY Equiangular and acute Which means all the inner angles are equal (60°).

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2 years ago
At graduation, ⅗ of the graduates received flowers. What percent did NOT receive flowers?
baherus [9]

Answer:

40%

Step-by-step explanation:

3/5=60%

100%-60%=40%

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Read 2 more answers
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

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3 years ago
All statements about opposite that are true.
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