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Stella [2.4K]
3 years ago
10

What type of error is present in the underlined

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

Type of error: <u>Run-on(comma splice).</u>

Best revision to fix it: <u>Adding a semicolon after beginners </u>.

Explanation:

A run-on sentence is described as a sentence in which two independent clauses are joined inappropriately. It could be either comma splice where the two independent clauses are incorrectly linked using a comma or fused sentence when the two clauses run-on without employing appropriate coordinating conjunction or punctuation marks to separate the two ideas.

In the given sentence, it exemplifies a comma splice type of run-on sentence error. To fix this error, a semicolon after 'beginners' can be employed instead of a comma. This <u>will help in connecting the two ideas appropriately where the first idea leads the second</u>. Thus, the final sentence reads as:

'The guitar is another excellent instrument for beginners; however, it takes more practice than a recorder.'

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Answer:

a) The 98% confidence interval for the population proportion of males who identify themselves as the primary grocery shopper is (0.457, 0.503).

b) The null hypothesis that the proportion is equal or less than 44% will be rejected at this level of significance.

c) The level of significance is 2%.

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Step-by-step explanation:

a) The conditions are:

- randomization: it is assumed to be a random sample.

- independence: the sample responses are independent of each other.

- 10% condition: we don't know the size of the population, but the sample is assumed to be less than 10% of the population.

- sample size: the sample size is bigger than 30, so it is satisfied.

We have to calculate a 98% confidence interval for the proportion.

The sample proportion is p=0.48.

p=X/n=1225/2550=0.48

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.48*0.52}{2550}}\\\\\\ \sigma_p=\sqrt{0.0001}=0.0099

The critical z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=2.326 \cdot 0.0099=0.023

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.48-0.023=0.457\\\\UL=p+z \cdot \sigma_p = 0.48+0.023=0.503

The 98% confidence interval for the population proportion of males who identify themselves as the primary grocery shopper is (0.457, 0.503).

b) Our confidence interval tells us that there is 98% confidence that the true proportion o males who identify themselves as the primary grocery shopper is within 0.457 and 0.503.

The propotion 0.44 is outside of this interval, so if the claim is that the proportion is higher than 44%, the null hypothesis will state that the true proprotion is equal or less than 0.44.

With the information we have, at this level of significance (2%), the null hypothesis will be rejected.

c) The level of significance that corresponds to the 98% confidence interval is α=2%.

This is the expected probability that the sample proportion fall outside the acceptance region (which matches with the confidence interval) due to pure chance, if the null hypothesis is true.

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