First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10
an = a1 * r^(n-1)
n = term to find = 5
a1 = first term = 120
r = common ratio = 3/10
now we sub and solve
a5 = 120 * 3/10^(5 - 1)
a5 = 120 * 3/10^4
a5 = 120 * .0081
a5 = 0.972 <=== fifth term
or we could have just done this......since we multiply by 3/10 to find the next number...
a3 = 10.8......10.8 * 3/10 = 3.24 <== 4th term
3.24 * 3/10 = 0.972 <== fifth term
Answer:
One forth of 20 is 5, so there are 5 kindergarten and first grade classrooms.
5 x 2 is 10 so there are 10 second and third grade classrooms.
10 + 5 is 15.
20 - 15 is 5.
There are 5 forth and fifth grade classes.
Step-by-step explanation:
Answer:
There are 8 girls
Step-by-step explanation:
We see that right now there are 6 more boys than girls and if there were 2 girls there would be 14 boys meaning there would be 12 more boys than girls if you continue in this pattern you would get-
7:1= 6 more boys 35:5=30 more boys
14:2= 12 more boys 42:6= 36 more boys
21:3=18 more boys 49:7= 42 more boys
28:4= 24 more boys 56:8= 48 more
This shows us that if there are 8 girls in group there are 56 boys meaning there are 48 more boys than girls if the group had 8 girls
Answer:
what
Step-by-step explanation:
why would you even need to know this
You can either round to 1000 or 2000 but 1.120 is closer to 1000
