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2 years ago

Which compound inequality can be used to solve the inequality 3x+2>7

Mathematics

1 answer:

kipiarov [429]2 years ago

3 0

Answer:

3x + 2 < –7 or 3x + 2 > 7

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A fair rents a thrill ride for $3000. It cost $4 to purchase a token for the ride. Write and solve an inequality to determine th

maria [59]

Answer:

938

Step-by-step explanation:

Given that :

Amount spent by fair on thrill. Ride = $3000

Cost per token of thrill ride = $4

For the fair to make a profit of atleast $750

Then it must realize : (cost of thrill ride + $750) = ($3000 + $750) = $3750

Therefore ;

Cost per token * number of rise tokens ≥ $3750

Let number of ride tokens = x

4x ≥ 3750

4x/4 ≥ 3750/4

x ≥ 937.5

Hence, number of tokens that must be sold = 938

4 0

2 years ago

Where does the $13876447 come from?

Lena [83]

Answer:

Trees

Step-by-step explanation:

trees are cut down. and made into money

3 0

3 years ago

Complete the diagram to find 430 percent of 90

ludmilkaskok [199]

The easiest way to find percent is to make the percent into a decimal and multiply. Move the decimal to places to the left to make 4.30, and multiplied by 90 equals 387, so 430 percent of 90 is 387.

3 0

3 years ago

Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

4 0

2 years ago

If the measure of an angle is 27°,find the measure of its supplement.

finlep [7]

Answer:

153°

Step-by-step explanation:

1. If 27° is the supplement of another angle (or vice versa), that means both angles add up to 180.

2. To find the supplement of 27°, we simply subtract that number from 180.

180 - 27
153

Therefore, the supplement of 27° is 153°.

3 0

2 years ago

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