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Cloud [144]
3 years ago
12

PLSS HELP MATHH !!!!12/11 - ( -2/3 ) = ?

Mathematics
1 answer:
Digiron [165]3 years ago
4 0
The answer should be 58/33 or 1 25/33
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Find the midpoint M of the line segment joining the points C = (-1, 1) and D = (5, – 7).<br> =<br> =
lukranit [14]

Answer: (2,-3)

Step-by-step explanation:

5 0
2 years ago
The equation of function h is h... PLEASE HELP MATH
Flura [38]

Answer:

Part A: the value of h(4) - m(16) is -4

Part B: The y-intercepts are 4 units apart

Part C: m(x) can not exceed h(x) for any value of x

Step-by-step explanation:

Let us use the table to find the function m(x)

There is a constant difference between each two consecutive values of x and also in y, then the table represents a linear function

The form of the linear function is m(x) = a x + b, where

  • a is the slope of the function
  • b is the y-intercept

The slope = Δm(x)/Δx

∵ At x = 8, m(x) = 2

∵ At x = 10, m(x) = 3

∴ The slope = \frac{3-2}{10-8}=\frac{1}{2}

∴ a = \frac{1}{2}

- Substitute it in the form of the function

∴ m(x) = \frac{1}{2} x + b

- To find b substitute x and m(x) in the function by (8 , 2)

∵ 2 = \frac{1}{2} (8) + b

∴ 2 = 4 + b

- Subtract 4 from both sides

∴ -2 = b

∴ m(x) = \frac{1}{2} x - 2

Now let us answer the questions

Part A:

∵ h(x) = \frac{1}{2} (x - 2)²

∴ h(4) = \frac{1}{2} (4 - 2)²

∴ h(4) = \frac{1}{2} (2)²

∴ h(4) =  \frac{1}{2}(4)

∴ h(4) = 2

∵ m(x) = \frac{1}{2} x - 2

∴ m(16) =  \frac{1}{2} (16) - 2

∴ m(16) = 8 - 2

∴ m(16) = 6

- Find now h(4) - m(16)

∵ h(4) - m(16) = 2 - 6

∴ h(4) - m(16) = -4

Part B:

The y-intercept is the value of h(x) at x = 0

∵ h(x) = \frac{1}{2} (x - 2)²

∵ x = 0

∴ h(0) = \frac{1}{2} (0 - 2)²

∴ h(0) =  \frac{1}{2} (-2)² =  

∴ h(0) = 2

∴ The y-intercept of h(x) is 2

∵ m(x) = \frac{1}{2} x - 2

∵ x = 0

∴ m(0) = \frac{1}{2} (0) - 2 = 0 - 2

∴ m(0) = -2

∴ The y-intercept of m(x) is -2

- Find the distance between y = 2 and y = -2

∴ The difference between the y-intercepts of the graphs = 2 - (-2)

∴ The difference between the y-intercepts of the graphs = 4

∴ The y-intercepts are 4 units apart

Part C:

The minimum/maximum point of a quadratic function f(x) = a(x - h) + k is point (h , k)

Compare this form with the form of h(x)

∵ h = 2 and k = 0

∴ The minimum point of the graph of h(x) is (2 , 0)

∵ k is the minimum value of f(x)

∴ 0 is the minimum value of h(x)

∴ The domain of h(x) is all real numbers

∴ The range of h(x) is h(x) ≥ 2

∵ m(8) = 2

∵ m(14) = 5

∵ h(8) = \frac{1}{2} (8 - 2)² = 18

∵ h(14) = \frac{1}{2} (14 - 2)² = 72

∴ h(x) is always > m(x)

∴ m(x) can not exceed h(x) for any value of x

<em>Look to the attached graph for more understand</em>

The blue graph represents h(x)

The green graph represents m(x)

The blue graph is above the green graph for all values of x, then there is no value of x make m(x) exceeds h(x)

7 0
3 years ago
Over a three-week period, Abram spent 15
denis23 [38]

Answer:

20 hours

Step-by-step explanation:

First off, if we divide the number of hours he has played by the number of weeks 15/3 =

It would be an average of <u>5 hours per week</u>

Therefore, in the next 4 weeks we would practice for 20 more hours.

i hope this helps you<33

have a nice day or night

7 0
2 years ago
The school board has approved the addition of a new sports team at your school.
motikmotik

Answer:

210

Step-by-step explanation:

1: Part/whole=%/100

2: 100-5=95

3: 3150/30=$105 uniforms.

Answer: $210

<em><u>Hope this helps.</u></em>

6 0
3 years ago
Which expression is equivalent to <img src="https://tex.z-dn.net/?f=%5Csqrt128x%5E%7B8%7D%20y%5E%7B3%7D%20z%5E%7B9%7D" id="TexFo
Elis [28]

Answer:

(C)8x^4z^4\sqrt{2yz}

Step-by-step explanation:

We want to determine an expression equivalent to: \sqrt{128x^8y^3z^9}

\sqrt{ab} =\sqrt{a}*\sqrt{b}

Therefore:

\sqrt{128x^8y^3z^9}=\sqrt{128}*\sqrt{x^8}*\sqrt{y^3}*\sqrt{z^9}

=\sqrt{64*2}*\sqrt{x^{4*2}}*\sqrt{y^{2+1}}*\sqrt{z^{8+1}}\\=8\sqrt{2}*\sqrt{x^{4*2}}*\sqrt{y^2*y}*\sqrt{z^{8}*z}}

=8\sqrt{2}*x^4*y \sqrt{y}*z^4\sqrt{z}\\=8*x^4*z^4*\sqrt{2}*\sqrt{y}*\sqrt{z}\\=8x^4z^4\sqrt{2yz}

4 0
3 years ago
Read 2 more answers
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