Diane Sweeney student centered coaching is known to be a tool that is made a Results Based Coaching Tool which a person can use to in a coaching cycle.
<h3>What is the coaching tool about?</h3>
This tool is known to be one that is often used to put down the impact of teacher and student learning in all of a coaching cycle.
What are the Core Practices that is made for Student Centered Coaching; They include:
1. A person Setting goals that are meant for coaching cycles.
2. The use of a given standards-based learning targets.
3. The use of student evidence in the act of co-plan instruction.
4. The act of Organizing coaching in cycles.
6. Measuring the influence of coaching.
Note that it was made to Improve student outcomes in regards to data-driven coaching and it is said to be a kind of Student-Centered Coaching made on the fact that school-based coaching can be set up to directly influence student learning.
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Answer:
Solving for the Percent by Volume
The v/v concentration of acetic acid in the stop bath is 24.6%.
Explanation:
To answer the question, we need to identify certain information stated in the question. Let us write down what’s given:
Volume of solute = 160 mL
Volume of solution = 650 mL
Next, we need to determine what is required, in this case, the percent by volume. Now, let us look at the formula:
v/v concentration = (solute volume / volume of the solution) * 100
Solution:
Percent by Volume = (160 / 650) * 100
Percent by Volume = 0.2461538461538462 * 100
Percent by Volume = 24.61538461538462
Rounded off = 24.6%
Therefore, the final answer is 24.6%
Explanation:
To promise a constitution
Inequalities are used to represent unequal expressions.
The solution set to
is: 
The inequality is given as:

From the inequality above, we have the following observation.
- The value of variable x starts from 7/16 (inclusive)
- The value of variable x has no end (i.e. infinity)
Because, 7/16 is inclusive of the values of x, we make use of the open square bracket i.e. [
We treat
, as an exclusive value. So, we make use of the close parenthesis i.e. )
Hence, the solution set is: 
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