We have this equation:

First, combine both logarithms using the multiplication property and simplify the expression.
![\log[x(x + 99)] = 2](https://tex.z-dn.net/?f=%5Clog%5Bx%28x%20%2B%2099%29%5D%20%3D%202)
![\log[ {x}^{2} + 99x ] = 2](https://tex.z-dn.net/?f=%5Clog%5B%20%7Bx%7D%5E%7B2%7D%20%2B%2099x%20%5D%20%3D%202)
Now, use the definition of logarithm to transform the equation.


Finally, use the quadratic formula to solve the equation.

With this, we can say that the solution set is:
We cannot choose x = -100 as a solution because we cannot have a negative logarithm. The only solution is x = 1.
D because there are 8 outcomes
The answer is 0.3333. Hope this helps!
Answer:
A) 1
Step-by-step explanation:
To solve, just plug in the numbers to the equation for x until both sides are equal to each other.
Plug in 1:
2(1 + x) = x + 3
Let x = 1:
2(1 + 1) = 1 + 3
Solve. Remember to follow PEMDAS. First, add parenthesis, then multiply. On the other side, add:
2(1 + 1) = 1 + 3
2(2) = 4
4 = 4 (True)
A) 1 is your answer.
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Answer: x = 32 y = 20
Step-by-step explanation:
114 = 3x + 18 114 = 3(y + 18)
-18 - 18 /3 /3
= =
96 = 3x 38 = y + 18
/3 /3 -18 -18
= =
32 = x 20 = y