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2 years ago

5x - 8y = 20 what are x and y? :)

Mathematics

2 answers:

Alex_Xolod [135]2 years ago

8 0

Answer:

x could be 10

y could be 5

those are some possible answers.

In-s [12.5K]2 years ago

7 0

Answer:

x=4 and y=0

(4,0)

hope I help or maybe correct

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Answer:

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Step-by-step explanation:

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2 years ago

F(x)=(x+2)^3-4<br> What is the slope?

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2 years ago

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The first jumbo jet was the Boeing 747, which is 70.5 meters long. The wingspan of a 747 is 60 meters. A model 747 has a wingspa

nydimaria [60]

Answer:

94 cm

Step-by-step explanation:

Set up and solve an equation of ratios:

wingspan length

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----------------- = ----------------

80 cm x

Cross multiplying:

(60 m)x = (70.5 m)(80 cm)

Solve for x by dividing both sides of this equation by 60 m:

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The length of the model should be 94 cm.

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3 years ago

LOL ANOTHER MATH QUESTION ASAP!!!

Inessa05 [86]

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3 years ago

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Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

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3 years ago