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andre [41]
3 years ago
14

Jack and Jill had a lemonade stand. At the end of the day they had 75 buckles and quarters totaling $6.75. How many of each type

of coin do they have?
Mathematics
1 answer:
vekshin13 years ago
8 0

Answer:

eat stool hahahahahahaahahah

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FOR 15 POINTS I WILL GIVE BRAINLEST IF YOU ARE CORRECT! What is the solution to the system that is created by the equation y = 2
goblinko [34]

The solution point is (4,2).

Step-by-step explanation:

Equation of straight line passing through the points (0,0) and (4,2) is given by

⇒ 2y = x ............ (1)

And the other straight line is y = - x + 6 .............. (2)

Now, solving equations (1) and (2) we get, y = - 2y + 6

⇒ 3y = 6

⇒ y = 2

And from equation (1) we get, x = 2y = 4

Therefore, the solution point is (4,2). (Answer)

6 0
3 years ago
Read 2 more answers
Adam has 3 coins in his pocket and they are all different from each other. Ben has 3 coins in his pocket and they are all the sa
Elenna [48]

Answer:

The possible coins are:

P = penny = $0.01

N = nickel = $0.05

D = dime = $0.10

Q = quarter = $0.25

H = half dollar = $0.50

We know that Adam has 3 coins in his pocket, and all of them are different, then the money that Adam has can be represented with (A + B + C)

Behn has 3 coins, and all of them are the same, then if his coin has a value X, he has a total of 3*X

We know that Adam has half as much money as Ben, this can be written as:

(A + B + C) = 3*X/2

The easier way to solve this, is to play with different values of X, and see if we can find the values of A, B and C.

For example, if X = $0.10

then:

(A + B + C) = $0.10*(3/2) = $0.15

We can find 3 different value of coins for this equation? No, we cant, so X = $0.10 is also discarded.

if x = $0.50 then:

(A + B + C) = (3/2)*$0.50 = $0.75

Here we could have:

A = $0.50

B = $0.25

then: A + B = $0.75

But we still have the coin C.

If we take X = $0.25 then:

(A + B + C) = (3/2)*$0.25 = $0.375

We could round the right part to $0.40

then the coins in the left part would be:

A = $0.25

B = $0.10

C = $0.05

A + B + C =  $0.25 + $0.10 +  $0.05 = $0.40

This is a strech, but is the only thing we can make with the given problem.

5 0
3 years ago
Change 6.00pm to 24 hours clock time<br><br>use a colon <br><br>​
kkurt [141]

Answer:

<h3>18:00 </h3>

Step-by-step explanation:

6:00 PM equals 18:00 in 24 hrs clock time.

<h3>Hope it helps you.. </h3>

3 0
3 years ago
Find the area of the shaded region.
taurus [48]

Answer:

426.96 \:  {km}^{2}

Step-by-step explanation:

Area of the shaded region = Area of triangle with base 40 km and height 27 km - Area of circle with radius (12/2) 6 km.

=  \frac{1}{2}  \times 40 \times 27  - 3.14 \times  {(6)}^{2}  \\  \\  = 20 \times 27 - 3.14 \times 36 \\  \\  = 540 - 113.04 \\ \\   = 426.96 \:  {km}^{2}

5 0
3 years ago
Find the TWO integers whos product is -12 and whose sum is 1<br>​
julsineya [31]

Answer:

\rm Numbers = 4 \ and \ -3.

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}

Hence the numbers are 4 and -3

5 0
3 years ago
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