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trapecia [35]
2 years ago
8

The ratio of the length to width of a rectangle is 3:4 the perimeter is 56 in, find the length and the width

Mathematics
1 answer:
Verizon [17]2 years ago
7 0

Answer: Length is 12in and width is 16in

Let's use the ratio method!

3+3+4+4 is 14

Let's think the length as," L " and the width as," W "

L / 56 = 3/14

L = 3/14 * 56

L = 12

And for width:

W / 56 = 4/14

W =4/14 * 56

W = 16

There you go! We did it!

Now make sure to click the Brainliest button if I gave the correct answer

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Hello, when x tends to \infty the term with the highest degree will lead the behaviour.

In other words.

\displaystyle \lim_{x\rightarrow+\infty} {x^4+3x^3-2x+7}\\\\=\lim_{x\rightarrow+\infty} {x^4}\\\\=+\infty\\\\\\\displaystyle \lim_{x\rightarrow-\infty} {x^4+3x^3-2x+7}\\\\=\lim_{x\rightarrow-\infty} {x^4}\\\\=+\infty

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7 0
4 years ago
1 point
swat32

Answer:

\log_{10}(147) = 2.1673

Step-by-step explanation:

Given

\log_{10} 3 = 0.4771

\log_{10} 5 = 0.6990

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\log_{10} 11 = 1.0414

Required

Evaluate \log_{10}(147)

Expand

\log_{10}(147) = \log_{10}(49 * 3)

Further expand

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Apply product rule of logarithm

\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)

Substitute values for log(7) and log(3)

\log_{10}(147) = 0.8451 + 0.8451 + 0.4771

\log_{10}(147) = 2.1673

3 0
3 years ago
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