Answer:
Hey! The answer is 25,4 centimeters.
Step-by-step explanation:
In a linear function you can use y=mx+n
So if x = hours and y= height.
You know that

So:
If you multiply (24,8=26m +n) x-1
It is: -24,8 = -26m -n
Adding up the other equation
-24,8 = -26m -n
<u>27,8 = 11m + n</u>
<u>3 = -15m</u>
<u>m= -0,2</u>
So
27,8 = 11 x 0,2 + n
27,8 = -2,2 + n
30 = n
This results that te linear function for this equation is:
y = -0,2x + 30
The answer is
y=23(-0,2) + 30
y=-4,6+30
y=25,4
You can rewrite the second equation because you know what y equals, so you can write it as 2x + x + 3 = 9
3x + 3 = 9
- 3
3x = 6
÷ 3
x = 2
And now you use the equation of what y equals and substitute in the value of x, so y = 2 + 3
y = 5
So your final answer is A. (2, 5). I hope this helps!
Answer:
Step 1: 8 + 16x Step 2: 4(4) + 4(12x) Step 3: 4(4 + 12x) Step 4: Dimensions of the rectangle are 4 and 4 + 12x In which step did the student first make an error and what is the correct step? Step 3; 4 + (4 + 12x) Step 3; 4 + (4 ⋅ 12x) Step 2; 4(2) + 4(4x) Step 2; 4(2) + 4x(2)
Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;
- 1. Arcs are drawn to cross the given line twice on either side relative to the point
- 2. The perpendicular line is drawn using a straight edge by connecting the small arcs formed using the arcs from step 1, to the point on the line or off the line
Description:
1. One of the first steps is to place the compass on the point and from
point, draw arcs to intersect or cross the given line at two points.
2. The compass is placed at each of the intersection point in step 1 and
(opened a little wider when constructing from a point on the line) arcs are
drawn on one (the other side of the point off the line) side of the line with
the same opening (radius) of the compass to intersect each other.
3. From the point of intersection of the arcs in step 2, a line is drawn with a
straight edge passing through the given point.
Learn more about perpendicular lines here:
brainly.com/question/11505244