Question

Which equation of a line contains point (-2,8) and is perpendicular to y = kx + 3? 6 (12)​

Answer 1

Answer: y - 8 = -6(x - 2)

Step-by-step explanation:

• slope

$m _{1} \times m _{2} = - 1 \\ \\ \frac{1}{6 } \times m _{2} = - 1 \\ \\ m = - 6$

• At point (-2, 8):

$y = mx + c \\ 8 = ( - 6 \times - 2) + c \\ 8 = 12 + c \\ c = - 4$

• equation

$y = - 6x - 4$